The class starts out with 26 students, of whom 12 are girls and, perhaps unlike Mr Morris, are sure of it.
The probability of the first random choice being a girl is 12/26. If successful, there are now 25 students left, of whom 11 are girls. The probability of a girl on the 2nd random choice is 11/25. The probability that BOTH random choices are successful is (12/26) x (11/25). That's (132/650), or about 20.31% (rounded).
Consider this option:
1. area_rombus=a*h, where a=6 - the length of the side, h - height.
h=area_rombus/a.
2. area_sq=a², where a=6 - the length of the square.
area_sq=36, area_rombus=4/5 *36=28.8.
3. according to the item 1 h=area_rombus/a=28.8/6=4.8.
answer: 4.8
Answer:
0.00466
Step-by-step explanation:
8+7+10+6 = 31
(8C2×7C3×10C4×6C5) ÷ 31C14
= 0.004656415426
= 0.00466 (3 sf)