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aliina [53]
2 years ago
15

Which terms could have a greatest common factor of 5m2n2? .

Mathematics
1 answer:
Mariana [72]2 years ago
6 0

Answer:

5m^4n^3

15m^2n^2

Step-by-step explanation:

Given :GCF is  5m^2n^2

m^5 n^5 : there is no 5 so GCF is not 5m^2n^2

5m^4n^3: GCF m^2, exponent 2 is less than exponent 4 . also GCf n^2 , exponent 2 is less than exponent 3. So GCf is 5m^2 n^2

10m^4n: GCF n^2 , exponent 2 is greater than exponent 1. so it does not have GCF

15m^2n^2 : 15 is 3*5 . so it has GCf is 5 m^2n^2

24m^3n^4: 24 is 3*2*2*2 . it does not have 5 . so GCF is not 5m^2n^2

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Is <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B6%7D%20" id="TexFormula1" title=" \frac{3}{6} " alt=" \frac{3}{6} "
STALIN [3.7K]

Hey!

-----------------------------------------

Answer: Yes 3/6 is rational!

-----------------------------------------

Why? Well, because 3 and 6 are integers that don't repeat. 3/6 simplifies to 1/2 or 0.5 which doesn't repeat so it's rational.

-----------------------------------------

Hope This Helped! Good Luck!

8 0
3 years ago
three friends are in the same algebra class. Their scores on a recent test are three consecutive odd intergers whose sum is 279.
jasenka [17]
X= 1st integer
x+2= 2nd integer
x+4= 3rd integer

Add the integers together

x + (x + 2) + (x + 4)= 279
combine like terms
3x + 6= 279
subtract 6 from both sides
3x= 273
divide both sides by 3
x= 91 first integer

Substitute x=91 to find 2nd & 3rd integers

2nd Integer
=x+2
=91+2
=93

3rd Integer
=x+4
=91+4
=95

ANSWER: The three test scores are 91, 93 and 95.

Hope this helps! :)
7 0
2 years ago
The value of y varies inversely with x. what is the value of k when y=12.7 and x=8?
NISA [10]

Answer:

ccccc

Step-by-step explanation:

5 0
2 years ago
(I've been trying to figure this out for 3 days and I really need help)
liq [111]

Check the picture below.

since the diameter of the cone is 6", then its radius is half that or 3", so getting the volume of only the cone, not the top.

1)

\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \implies V\approx 37.7

2)

now, the top of it, as you notice in the picture, is a semicircle, whose radius is the same as the cone's, 3.

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=3 \end{cases}\implies V=\cfrac{4\pi (3)^3}{3}\implies V=36\pi \\\\\\ \stackrel{\textit{half of that for a semisphere}}{V=18\pi }\implies V\approx 56.55

3)

well, you'll be serving the cone and top combined, 12π + 18π = 30π or about 94.25 in³.

4)

pretty much the same thing, we get the volume of the cone and its top, add them up.

\bf \stackrel{\textit{cone's volume}}{\cfrac{\pi (3)^2(8)}{3}}~~~~+~~~~\stackrel{\stackrel{\textit{half a sphere}}{\textit{top's volume}}}{\cfrac{4\pi 3^3}{3}\div 2}\implies 24\pi +18\pi \implies 42\pi ~~\approx~~131.95~in^

8 0
3 years ago
True or False The Solutions, Roots, X-intercepts and zeros of a quadratic equation are all the same thing? why
Zepler [3.9K]

Yes, solutions, roots, x-intercepts, and zeros are the same thing.

<h3>What is a quadratic equation?</h3>

The general quadratic equation is given by:

a*x^2 + b*x + c = 0

So the solutions are the values of x such that the above thing is zero.

On another hand, a parabola or a quadratic function is given by:

a*x^2 + b*x + c = y

The roots, zeros, or x-intercepts (these represent the same thing) are given by:

a*x^2 + b*x + c = 0

  • Zero or Root means that when you evaluate the function in that value the outcome is zero.
  • X-intercept means that for that value of x, the function intercepts the x-axis, so the function is equal to zero.

So these are the values of x such that the function becomes equal to zero, so these are exactly the same thing as the solutions of a quadratic equation.

Concluding, yes, solutions, roots, x-intercepts, and zeros are the same thing.

If you want to learn more about quadratic functions, you can read:

brainly.com/question/1214333

8 0
2 years ago
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