Answer: $105
Step-by-step explanation:
Answer:
<em>(x - 2)^2 + (y + 1)^2 = 26</em>
Step-by-step explanation:
A circle with center O(2, -1) that passes through the point A(3, 4).
=> The radius of this circle is OA which could be calculated by:
OA = sqrt[(3 - 2)^2 + (4 - (-1))^2] = sqrt[1^2 + 5^2] = sqrt[26]
The equation of a circle with center O(a, b) and radius r could be written as:
(x - a)^2 + (y - b)^2 = r^2
=> The equation of circle O above with center O(2, -1) and radius = sqrt(26) is shown as:
(x - 2)^2 + (y - (-1))^2 = (sqrt(26))^2
<=>(x - 2)^2 + (y + 1)^2 = 26
Hope this helps!
<span><u><em>The correct answer is:</em></u>
$42.
<u><em>Explanation:</em></u>
The best way to find a total bill including tip (or tax if that is what you are looking for - it is found the same way), is to multiply the original total by 1 + the percentage of the tip.
Since the percentage is 20%, we add 0.20 to 1 to get 1.20.
Now we multiply that by the original cost to get the final answer.
1.20*35 = 42</span>
Answer:
25/324
Step-by-step explanation:
Make a table of possible products:
![\left[\begin{array}{ccccccc}&1&2&3&4&5&6\\1&1&2&3&4&5&6\\2&2&4&6&8&10&12\\3&3&6&9&12&15&18\\4&4&8&12&16&20&24\\5&5&10&15&20&25&30\\6&6&12&18&24&30&36\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccccc%7D%261%262%263%264%265%266%5C%5C1%261%262%263%264%265%266%5C%5C2%262%264%266%268%2610%2612%5C%5C3%263%266%269%2612%2615%2618%5C%5C4%264%268%2612%2616%2620%2624%5C%5C5%265%2610%2615%2620%2625%2630%5C%5C6%266%2612%2618%2624%2630%2636%5Cend%7Barray%7D%5Cright%5D)
Of the 36 results, 10 are greater than 15.
The probability the product is greater than 15 on a single roll is 10/36 = 5/18.
The probability the product is greater than 15 on two rolls is (5/18)² = 25/324.
Answer:
<u>y = - 6.375</u>
Step-by-step explanation:
Step 1:
4 ( y - 3y ) - 19 = 32 Equation
Step 2:
4y - 12y - 19 = 32 Multiply
Step 3:
- 8y - 19 = 32 Combine Like Terms
Step 4:
- 8y = 51 Add 19 on both sides
Step 5:
y = 51 ÷ - 8 Divide
Answer:
<u>y = - 6.375</u>
Hope This Helps :)
