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dezoksy [38]
3 years ago
7

GCF of 3(x+2)^3 and 6(x+2)^2

Mathematics
1 answer:
Zina [86]3 years ago
6 0

Answer:

Greatest Common Factor is 3

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What is the product of 4 and 5g + 2.34?
PolarNik [594]

The product of 4 and 5g + 2.34 is 20g + 9.36

<h3>How to determine the product?</h3>

The expressions are given as:

4 and 5g + 2.34

As a product expression, we have:

4 * (5g + 2.34)

Evaluate the product

20g + 9.36

Hence, the product of 4 and 5g + 2.34 is 20g + 9.36

Read more about products at:

brainly.com/question/10873737

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6 0
2 years ago
Jamal has the following choices for his pizza: white sauce or red sauce; white cheese or yellow cheese; and mushrooms, pepperoni
Dimas [21]
There is a high probability don’t know if that we’ll help though
5 0
3 years ago
Read 2 more answers
A freezer has a volume of 54 ft.³ it has a length of 6 feet and a height of 3 feet what is the length of the width of the freeze
gogolik [260]
Ok so let’s see we have L and H but we don’t have the W so to find it we start by multiplying the numbers we do have which is L and H so 6x3=18 know that we did that we tasked the volume number which is 54 and we divide that by 18 so 54➗18 = 3 so our width is 3

Hope this helped :)
3 0
2 years ago
The denominator of a fraction is 4 more than the numerator. if both the numerator and the denominator of the fraction are increa
Olin [163]
(x+3)/((x+4)+3)=5/6
(x+3)/(x+7)=5/6
6(x+3)=5(x+7)
6x+18=5x+35
x=35-18
x=17
17/(17+4)=17/21
check : (17+3)/(17+4+3)=20/24=5/6
4 0
4 years ago
Write the equation to go with the given information.
DENIUS [597]

Answer:

Equation is;

(D/8) + (D/4) = 1600

D = 4266.67 ft

Step-by-step explanation:

We are told that the bee flies at a rate of 8ft/sec directly to a flowerbed from its hive. Thus,

speed during this stage is; v1 = 8ft/sec

Time during this stage is; t1

The bee stays at the flower bed for 1200 seconds.

Thus, time at this stage is; t2 = 1200 s

It flies directly back to the hive at 4ft/sec.

Speed at this stage; v2 = 4 ft/s

Time at this stage; t3

We are told that it was away for a total of 2800 seconds.

Thus; t1 + t2 + t3 = 2800

Since t2 = 1200 s, then;

t1 + 1200 + t3 = 2800

t1 + t3 = 2800 - 1200

t1 + t3 = 1600

Now, during time t1, the speed was 8ft/sec, since distance is equal to speed × time, then we have;

D = 8t1

t1 = D/8

During time t3, the speed was 4ft/sec. Thus; D = 4t3

t3 = D/4

Thus,since t1 + t3 = 1600

Then;

(D/8) + (D/4) = 1600

Multiply through by 8 to get;

D + 2D = 1600 × 8

3D = 12800

D = 12800/3

D = 4266.67 ft

7 0
3 years ago
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