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Tom [10]
4 years ago
11

What is the answer to this problem. -3(1.2)^2

Mathematics
1 answer:
djyliett [7]4 years ago
6 0

Remember to follow PEMDAS when solving.

= -3(1.2)^2

= -3(1.44)

= -4.32

Hope This Helped! Good Luck!

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Ana took out a $600 loan from the bank. At the end of 5 years, she pays back $60 in interest. What was the interest rate?
Usimov [2.4K]

Answer:

Ana payed a 10% interest rate.

7 0
3 years ago
the grade 8 has hired a disk jockey the disk jockey takes 85$ plus 2 for each student that attends. The disk jockey was paid 197
Paha777 [63]

Answer:

56 students

Step-by-step explanation:

The equation for your question is 85+2x=197. First you would have to subtract 85, on both sides, leaving you with 2x=112. Then, you'd have to divide by 2 on both sides to isolate the variable. From there, you're left with x=56.

5 0
4 years ago
my teacher would like you to solve this using fraction ex:(345/x=727/2355) (just a heads up!!) please help :)​
Vitek1552 [10]

Answer:

84

Step-by-step explanation: (edited)

52% problems are pointless i.e. 48% are NOT pointless.

Recall that 1% = 1/100.

Therefore 48% = 48/100 = 12/25.

Let x be the number of problems that are not pointless.

x/175 = 12/25

x = 84

3 0
3 years ago
Read 2 more answers
Suppose the lengths of the pregnancies of a certain animal are approximately normally distributed with mean mu equals 280 days a
a_sh-v [17]
First, find the z-score:

z = (value - mean) / sdev
  = (275 - 280) / 15
  = - 0.33

In order to use a standard normal table, we need a positive z-score:
P(z < -0.33) = 1 - P(z < 0.33)

Looking at the table, we find P(z < 0.33) = 0.6293

Therefore:
P(z < -0.33) = 1 - 0.6293 = 0.3707

Hence, you have a probability of about 37% <span>that a randomly selected pregnancy lasts less than 275 days.</span>
4 0
3 years ago
Machine A can complete a certain job in x hours. Machine B can complete the same job in y hours. If A and B work together at the
scZoUnD [109]

Answer:

\frac{y}{x+y}

Step-by-step explanation:

The required answer is the rate at  which Machine A  works when the two machines are combined.

Note: the rate of doing work is express as

rate=\frac{1}{time taken} \\

Hence we can conclude that Machine A working rate is

machine A=\frac{1}{x} \\ and machine B working rate is

machine B=\frac{1}{y} \\

When the two machine works together, the effective working rate is

\frac{1}{x}+\frac{1}{y}\\\frac{xy}{x+y}\\

The fraction of the work that Machine B will not have complete because of Machine A help is the total work done by machine A

Hence the fraction of work done by A is expressed as

\frac{1}{x}*combine working rate

\frac{1}{x}*\frac{xy}{x+y}\\\frac{y}{x+y} \\

Hence the fraction of the work that Machine B will not have complete because of Machine A help is the total work done by machine A is \frac{y}{x+y} \\

6 0
3 years ago
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