Answer:
Step-by-step explanation:
for odd terms
first term=5
c.d.=8-5=3
odd terms are given by 5+3(n-1)=2+3n
for even terms
first term=10
c.d.=13-10=3
even terms are given by 10+3(n-1)=7+3n
H=vt-16t²
vt-16t²=H
vt=16t²+H
v=(16t²+H)/t
v=16(t²/t)+H/t
v=16t+H/t
Answer: the answer would be: v=16t+H/t
Given:
Giant panda population in 2014 = 1864
The giant panda population in China is increasing at a rate of 1.5% each year.
To find:
The function that models the panda population since 2014.
Solution:
Since population of giant panda is increasing, therefore the function is the exponential growth model.
The general exponential growth model is:
Where, 
is the initial population, r is the growth rate in decimal and t is the time period.
Putting 
, we get
Where, t is the number of years since 2014.
Therefore, the required exponential growth model is .
Answer:
-270
Step-by-step explanation:
120 down to -150= 270 decrease=(-270)
The equations (2) and (3) you referred to are unavailable, but it is clear that you are trying to show that two set of solutions y1 and y2, to a (second-order) differential equation are solutions, and form a fundamental set. This will be explained.
Answer:
SOLUTION OF A DIFFERENTIAL EQUATION.
Two functions y1 and y2 are set to be solutions to a differential equation if they both satisfy the said differential equation.
Suppose we have a differential equation
y'' + py' + qy = r
If y1 satisfies this differential equation, then
y1'' + py1' + qy1 = r
FUNDAMENTAL SET OF DIFFERENTIAL EQUATION.
Two functions y1 and y2 are said to form a fundamental set of solutions to a second-order differential equation if they are linearly independent. The functions are linearly independent if their Wronskian is different from zero.
If W(y1, y2) ≠ 0
Then solutions y1 and y2 form a fundamental set of the given differential equation.
