Simplify the product. Write the answer in standard form.<br>(x2 + 4)(x+3)

What is the Lateral area of this prism ?

Mazyrski [523]

Answer:

idk let me go look at it

Step-by-step explanation:

5 0

2 years ago

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Please help Please help Please help Please help Please help Please help Please help Please help Please help Please help Please h

Alika [10]

X is side to side
Y is down to up

7 0

1 year ago

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A number when divided by 899 gives a remainder 63. If the same number is divided by 29, then the remainder will be :

elena55 [62]

x = 899xy + 63

29x31xy + 29x^2+5

29(31y+2)+85

=29

63-58=5

The remainder will be 5.

7 0

3 years ago

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Given u = LeftAngleBracket StartRoot 3 EndRoot, negative 1 RightAngleBracket and v = ⟨3, –4⟩, what is u · v?

Evgesh-ka [11]

Answer:

3√3+4

Step-by-step explanation:

Given the vectors u = <√3, -1> and v = <3, -4>

u · v = <√3, -1> *<3, -4>

u · v = 3√3 + (-1*-4)

u · v = 3√3+(4)

u · v = 3√3+4

Hence the dot product is 3√3+4

5 0

3 years ago

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Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0

2 years ago

Simplify the product. Write the answer in standard form.(x2 + 4)(x+3)​

Simplify the product. Write the answer in standard form.(x2 + 4)(x+3)