Answer: The correct option is (A). When the radicand is negative
Step-by-step explanation: We are given to select the correct option by which we can tell that a quadratic equation has no real solutions.
We know that for the quadratic equation
the radicand is given by
Based on the radicand "D", we have the following rules:
(i) If D > 0 (positive), then the two solutions are real and unequal.
(ii) If D = 0, then the two solutions are equal.
(iii) If D< 0 (negative), then the two solutions are complex (not real).
Thus, when the radicand is negative, then the quadratic equation has no real solutions.
Option (A) is correct.
I don’t know this answer but I think it’s 81
Answer:
you decude to go put for a walk. You walk 8km to the north in 2 hours, then you walk 3km to the south in 1 houryou decude to go put for a walk. You walk 8km to the north in 2 hours, then you walk 3km to the south in 1 houryou decude to go put for a walk. You walk 8km to the north in 2 hours, then you walk 3km to the south in 1 houryou decude to go put for a walk. You walk 8km to the north in 2 hours, then you walk 3km to the south in 1 hour 6655.22591
One approach is to express
8x2y
so that the numerator and denominator are expressed with the same base. Since 2 and 8 are both powers of 2, substituting 23 for 8 in the numerator of 8x2y gives
(23)x2y
which can be rewritten
23x2y
Since the numerator and denominator of have a common base, this expression can be rewritten as 2(3x−y). In the question, it states that 3x−y=12, so one can substitute 12 for the exponent, 3x−y, which means that
8x2y=212
The final answer is A.
