The answer is a I believe
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Answer:
69.14% probability that the diameter of a selected bearing is greater than 84 millimeters
Step-by-step explanation:
According to the Question,
Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.
- In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ
we have μ=87 , σ=6 & X=84
- Find the probability that the diameter of a selected bearing is greater than 84 millimeters
This is 1 subtracted by the p-value of Z when X = 84.
So, Z = (84-87)/6
Z = -3/6
Z = -0.5 has a p-value of 0.30854.
⇒1 - 0.30854 = 0.69146
- 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.
Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)
Answer:
their are 17 cows
Step-by-step explanation:
7x2=14
82-14=68
68/4=17
Answer:
$3063.6
Step-by-step explanation:
72% of $4,255 = $3063.6
The formula for finding percents is number x percent ÷ 100.
4,255 x 72 ÷ 100 = 3063.6
Answer:
m(∠W) = 114°
Step-by-step explanation:
By the property of a parallelogram,
"Opposite angles of a parallelogram are equal in measure"
By this property,
m(∠W) = m(∠U)
9x + 15 = 4 + 10x
15 - 4 = 10x - 9x
x = 11
Therefore, m(∠W) = 9x + 15
= 9(11) + 15
= 99 + 15
= 114°
Measure of angle W is 114°.
