Answer:
3. The class median is lower than the exam median
Step-by-step explanation:
The median of the box plot is indicated by the vertical line that divides the box.
Thus, the Class median grade is about 80, while the Exam median grade is more than 80.
Comparing grades, this means that the class median is lower. than the exam median.
Therefore, "the class median is lower than the exam median" is the right information that describes the median.
Answer:
all correct
Step-by-step explanation:
Answer:
Step-by-step explanation:
a)
p(d) - probability of a rivet being defective
p(r) - probability of seam needing to be reworked
The probability of the seem needing to be reworked is equal to the probability that ANY of 24 rivets is defective
Thus the probability that none of the 25 rivets is defective is 1-p(r)
p(r) = 16%, thus 1-p(r) = 84%
1-p(r) = (1-p(d))^24
0.84 = (1-p(d))^24
0.84^(1/24) = 1-p(d)
==> 1-p(d) = 0.9927615998
==> p(d) = 1-0.9927
==> p(d) = 0.0073
b) given p(r) = 8%, thus 1-p(r) = 92%
1-p(r) = (1-p(d))^24
0.92 = (1-p(d))^24
0.92^(1/24) = 1-p(d)
==> 1-p(d) = 0.99653179446
==> p(d) = 1-0.9965
==> p(d) = 0.0035
First, let us define our variables.
Let
x = age of the father
y = age of the son
z = age of the daughter
5 years ago..
(x – 5) = age of the father
(y – 5) = age of the son
(z – 5) = age of the daughter
After 18 years...
(x + 18) = age of the father
(y + 18) = age of the son
(z +18) = age of the daughter
From the first condition
y = z + 5 à
eqn 1
5 years ago
(x-5) = 23 + (y-5) + (z-5)
x –y –z = 18 à
eqn 2
after 18 years
(x+18) = 17*[(y +18 –z – 18)]
x – 17y + 17z = -18 à
eqn 3
solving the 3 equations simultaneously
x = 67
y = 27
z = 22
