Question

d = √ ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 Evaluate d if ( x 1 , y 1 ) = ( 0 , − 5 ) and ( x 2 , y 2 ) = ( 4 , − 3 ) . Leave your answer in surd form.

Answer 1

Answer:

$d=2\sqrt{5}$ units

Step-by-step explanation:

$\text{Distance, }d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ If ( x_1 , y_1 ) = ( 0 , - 5 ) and ( x_2 , y_2 ) = ( 4 , - 3 )\\\\d=\sqrt{(4-0)^2+(-3-(-5))^2} \\=\sqrt{4^2+(-3+5)^2}\\=\sqrt{4^2+2^2}\\=\sqrt{20}\\\\d=2\sqrt{5} units$