d = √ ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 Evaluate d if ( x 1 , y 1 ) = ( 0 , − 5 ) and ( x 2 , y 2 ) = ( 4 , − 3 ) . Leave your a

Question

Vlad1618 [11]

2 years ago

5

d = √ ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 Evaluate d if ( x 1 , y 1 ) = ( 0 , − 5 ) and ( x 2 , y 2 ) = ( 4 , − 3 ) . Leave your a

nswer in surd form.

Mathematics

1 answer:

Semmy [17] · Answer 1 · 2022-04-25T10:18:34+03:00

Semmy [17]2 years ago

8 0

Answer:

$d=2\sqrt{5}$ units

Step-by-step explanation:

$\text{Distance, }d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\$If ( x_1 , y_1 ) = ( 0 , - 5 )$ and ( x_2 , y_2 ) = ( 4 , - 3 )\\\\d=\sqrt{(4-0)^2+(-3-(-5))^2} \\=\sqrt{4^2+(-3+5)^2}\\=\sqrt{4^2+2^2}\\=\sqrt{20}\\\\d=2\sqrt{5}$ units$