Find percent notation 3/4

Mathematics

2 answers:

FrozenT [24]3 years ago

6 0

Answer:

the percent notation is 75%

Step-by-step explanation:

Fynjy0 [20]3 years ago

3 0

Answer:

75%

Step-by-step explanation:

You might be interested in

Antwan determines the distance between the points –7 and 2 on a numberline. Maggie determines the difference between the numbers

Orlov [11]

Answer:

Their solutions are related because they both are |9| (the absolute value of 9)

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

In order to determine whether or not a variable type of process is in control (whereoutput can be measured, not just classified

Tema [17]

Answer:

i dont know

Step-by-step explanation:

just working

6 0

3 years ago

The locus of points idea allows you to define a circle without giving a numerical value for the radius?

Lunna [17]

The answer would be yes, the locus of points idea allows you to define a circle without giving a numerical value for the radius.

A locus of points is the set of points, and only those points, that satisfies given conditions. The locus of points at a given distance from a given point is a circle whose center is the given point and whose radius is the given distance.

4 0

3 years ago

Read 2 more answers

Solve 2x^2 + x - 4 = 0 X2 +

damaskus [11]

Answer:

$\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }$

Step-by-step explanation:

Hello, please find below my work.

$2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0$

$\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}$