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REY [17]
2 years ago
7

The LCD for the fractions 1/3, 3/4, 5/32, and 8/9 is

Mathematics
1 answer:
tresset_1 [31]2 years ago
6 0
What is the smallest number divisible by 3, 4, 32 and 9?
You might want to try factoring these denominators and writing them in their factored form:

3, 2^2, 2^5, 3^2

Your LCD must include the following factors:  3^2 and 2^5, or 9 and 32.  Multiplying these together results in the correct LCD 9*32=288.

Check:  Is 288 divisible by 3?  Yes.  The quotient is 96.
Is 288 divisible by 4?  Yes.  Is 288 divisible by 32?  Yes.  Is 288 divisible by 9?  Yes.
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Need help!!! solve for p) n = <br>(p-k)<br> ------<br> j<br><br>Sorry for the terrible fraction
almond37 [142]

Answer:

nj +k = p

Step-by-step explanation:

n = (p-k)/j

Multiply each side by j

nj = (p-k)/j *j

nj = p-k

Add k to each side

nj +k p-k+k

nj +k = p

8 0
2 years ago
Read 2 more answers
The volume of a cubical box is 474.552m3.Find the length of each side of the box
Cerrena [4.2K]

The formula of a volume of a cube:

V=a^3

We have V=474.552\ m^3

Substitute:

a^3=474.552\to a=\sqrt[3]{474.552}\\\\a=7.8\ m

Answer: The length of each side of the box is equal 7.8 m.

8 0
2 years ago
Which of the following sets could be the sides of a right triangle?
MArishka [77]
In a right triangle the sum of the squares of the lengths of two shorter sides is equal to the square of the length of the longest side.

a.
2^2+3^2=(\sqrt{13})^2 \\&#10;4+9=13 \\&#10;13=13 \\ true

b.
2^2+2^2=4^2 \\&#10;4+4=16 \\&#10;8=16 \\&#10;not \ true

c.
1^2+(\sqrt{3})^2=2^2 \\&#10;1+3=4 \\&#10;4=4 \\&#10;true

The answer is A and C.
5 0
3 years ago
Read 2 more answers
There are 4 grams of sugar in 1⁄2 of a liter of a new sports drink. How much sugar is in 3⁄4 of a liter of the sports drink?
Ira Lisetskai [31]
The correct answer is 6 grams of sugar

Hope this helped :)
4 0
3 years ago
If a single card is drawn from a standard 52-card deck, what is the probability that it is an ace or a spade?
klasskru [66]

A 52-card deck is made up of an equal number of diamonds, hearts, spades, and clubs. Because there are 4 suits, there is a 1/4 chance to draw one of them, in our case, spades.

There are 4 aces in a 52-card deck, so the chance of drawing one is 4/52, or 1/13.

The question asks for the probability of drawing an ace or a spade. Because it uses the word "or," we add the probabilities together. This is because there is a chance of drawing either of the cards; it doesn't have to meet both requirements to satisfy the statement.

However, if the question were to say "and," we would multiply the two probabilities.

Let's add 1/4 and 1/13. First, we can find a common denominator. We can use 52 because both fractions can multiply into it (since the ratio came from a deck of 52 cards as well).

\frac{1}{4} -- > \frac{13}{52}

\frac{1}{13} -- > \frac{4}{52}

Now we can add them together.

\frac{13}{52} + \frac{4}{52} = \frac{13+4}{52} = \frac{17}{52}

This cannot be simplified further, so the probability is 17 in 52, or 33%.

hope this helps!

7 0
1 year ago
Read 2 more answers
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