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REY [17]
3 years ago
7

The LCD for the fractions 1/3, 3/4, 5/32, and 8/9 is

Mathematics
1 answer:
tresset_1 [31]3 years ago
6 0
What is the smallest number divisible by 3, 4, 32 and 9?
You might want to try factoring these denominators and writing them in their factored form:

3, 2^2, 2^5, 3^2

Your LCD must include the following factors:  3^2 and 2^5, or 9 and 32.  Multiplying these together results in the correct LCD 9*32=288.

Check:  Is 288 divisible by 3?  Yes.  The quotient is 96.
Is 288 divisible by 4?  Yes.  Is 288 divisible by 32?  Yes.  Is 288 divisible by 9?  Yes.
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(6x - 12)/3 + 4 = 18/x
svet-max [94.6K]
X=3
X=-3
Hope this help!
3 0
3 years ago
Domain and Range for this equation? F(x)= 3x^7+0x^6-0x^5-2x^4-3x^3-2x^2-x^1+x^0
sp2606 [1]
The domain is equal all real numbers
D=\mathbb{R}

The degrees of the polynomial is odd (3x^7, 7 is odd), therefore the range is equal all real numbers

R=\mathbb{R}
8 0
3 years ago
The length of an alligator in a zoo is 14 5/6 feet.The everglades national parks list the longest alligator ever reocord in flor
astraxan [27]

Answer:

The difference in the lengths of the two alligators = 3

Step-by-step explanation:

First, let us make the lengths improper fractions, then we will find the difference from there.

Alligator 1:

Length = 14\frac{5}{12} = \frac{173}{12}

To convert to improper fraction, multiply the denominator by the whole number, and then add the denominator [(12 × 14) + 5]

Alligator 2:

Length = 17\frac{5}{12} = \frac{209}{12}

Now Let us find the difference between the lengths:

\frac{209}{12} - \frac{173}{12} = \frac{36}{12} =3

Therefore the difference in the lengths of the two alligators = 3

3 0
3 years ago
Graph the line with the equation y=-1/2x-3
GrogVix [38]
Like this? Brainliest if I got it? :) it’s ok if u don’t

4 0
2 years ago
Determine if the conditional and its converse are true. If they are both true, select which biconditional correctly represents t
Ugo [173]
The conditional,  <span>If four points are non-coplanar, then they are non-collinear, </span>is true:

This is, coplanarity is a necessary condition to be collinear.

The converse, <span>If four points are non-collinear, then they are non-coplanar, is false.

A counterexample that disproves this statement is the 4 vertices of a paralelogram, of course they are in a same plane and are not collinear.
</span> 


3 0
3 years ago
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