The minimum or maximum value of a quantity are what are used to maximize or minimize a function.
<em>The method for finding these minimum or maximum value is linear programming.</em>
<em />
Take for instance, the following parameters:

Subject to:



The above is an illustration of a linear programming.
It is useful in the following areas:
- To formulate real life problems
- To get an optimal solution
- To maximize profit and minimize cost
- Etc
Read more about linear programming at:
brainly.com/question/14225202
Answer: 471.24
Step-by-step explanation:
V=πr2h=π·52·6≈471.2389
Answer:
E) we will use t- distribution because is un-known,n<30
the confidence interval is (0.0338,0.0392)
Step-by-step explanation:
<u>Step:-1</u>
Given sample size is n = 23<30 mortgage institutions
The mean interest rate 'x' = 0.0365
The standard deviation 'S' = 0.0046
the degree of freedom = n-1 = 23-1=22
99% of confidence intervals
(from tabulated value).





using calculator

Confidence interval is


the mean value is lies between in this confidence interval
(0.0338,0.0392).
<u>Answer:-</u>
<u>using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.</u>
19 = 19/1 = 38/2 = 57/3 = 76/4