Answer:for ax^2+bx+c=0 the discriminant is b^2-4ac
there are 3 basic cases of what happens for different discriminants
1. if the discriminant is less than 0, then there are no real zeroes
2. if the discriminant is 0, then it has 1 zero
3. if the discriminant is greater than 0, it has 2 zeroes
so given
0=3x^2-7x+4
a=3,b=-7,c=4
thus the discriminant is (-7)^2-4(3)(4)=49-48=1
the discriminant is 1. 1 is positive, thus the equation has 2 zeroes because the discriminant is greater than 0
the answer is the equation has two zeroes because the discriminant is greater than 0
Step-by-step explanation:
Answer:
Step-by-step explanation:
ok im not sure if this is it but 148.41315910
Answer:
The answer in C
Step-by-step explanation:
104-8= 96
96/4= 24.
Answer:
Part A) ![sin(A)=\frac{2\sqrt{42}}{23}](https://tex.z-dn.net/?f=sin%28A%29%3D%5Cfrac%7B2%5Csqrt%7B42%7D%7D%7B23%7D)
Part B) ![cos(A)=\frac{19}{23}](https://tex.z-dn.net/?f=cos%28A%29%3D%5Cfrac%7B19%7D%7B23%7D)
Part C) ![tan(A)=\frac{2\sqrt{42}}{19}](https://tex.z-dn.net/?f=tan%28A%29%3D%5Cfrac%7B2%5Csqrt%7B42%7D%7D%7B19%7D)
Step-by-step explanation:
Part A) we know that
In the right triangle ABC of the figure the sine of angle A is equal to divide the opposite side angle A by the hypotenuse
so
![sin(A)=\frac{BC}{AB}](https://tex.z-dn.net/?f=sin%28A%29%3D%5Cfrac%7BBC%7D%7BAB%7D)
substitute the values
![sin(A)=\frac{2\sqrt{42}}{23}](https://tex.z-dn.net/?f=sin%28A%29%3D%5Cfrac%7B2%5Csqrt%7B42%7D%7D%7B23%7D)
Part B) we know that
In the right triangle ABC of the figure the cosine of angle A is equal to divide the adjacent side angle A by the hypotenuse
so
![cos(A)=\frac{AC}{AB}](https://tex.z-dn.net/?f=cos%28A%29%3D%5Cfrac%7BAC%7D%7BAB%7D)
substitute the values
![cos(A)=\frac{19}{23}](https://tex.z-dn.net/?f=cos%28A%29%3D%5Cfrac%7B19%7D%7B23%7D)
Part C) we know that
In the right triangle ABC of the figure the tangent of angle A is equal to divide the opposite side angle A by the adjacent side angle A
so
![tan(A)=\frac{BC}{AC}](https://tex.z-dn.net/?f=tan%28A%29%3D%5Cfrac%7BBC%7D%7BAC%7D)
substitute the values
![tan(A)=\frac{2\sqrt{42}}{19}](https://tex.z-dn.net/?f=tan%28A%29%3D%5Cfrac%7B2%5Csqrt%7B42%7D%7D%7B19%7D)
Answer:
Dear user,
Answer to your query is provided below
2(al−1) is the expression equivalent for 2la+26−2−26