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3 years ago

Help me plzz you get 100 points

Mathematics

2 answers:

babymother [125]3 years ago

8 0

Answer:

A. B

B. C and D

Step-by-step explanation:

A: 2/3 * 7/7

7/7= 1 which is larger than 2/3

Mandarinka [93]3 years ago

3 0

Answer:

question 1 C. i dont know about question 2 i belive the answer is D.

Step-by-step explanation: srry but i did give it a try

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An expression is shown below:

coldgirl [10]

Answer:

3y(2 $x^{2}$ - 9x + 12y)

Step-by-step explanation:

Part A:

The GCF of 6, 3, 24, and 12 is 3:

so 3(2 $x^{2}$ y - xy - 8xy + 12 $y^{2}$ )

= 3(2 $x^{2}$ y - 9xy + 12 $y^{2}$ )

Also y is also common so:

= 3y(2 $x^{2}$ - 9x + 12y)

Part B:

3y(2 $x^{2}$ - 9x + 12y)

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4 years ago

What is the relationship between the 3's in number 9,338???

Serjik [45]

In the 2nd digit is worth 300. In the 3rd digit it is worth 30.

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3 years ago

Read 2 more answers

Review the proof step statement 1 cos(2x) = 1-sin^2(x)

ehidna [41]

Answer:

Option (3)

Step-by-step explanation:

Correct steps for the proof are,

Step Statement

1 cos(2x) = 1 - 2sin²(x)

2 Let 2x = θ

3 x = $\frac{\theta}{2}$

4 $\text{cos}\theta = 1 - 2\text{sin}^2(\frac{\theta}{2} )$

5 $\text{cos}\theta-1 =-2\text{sin}^2(\frac{\theta}{2} )$

6 $1-\text{cos}\theta =2\text{sin}^2(\frac{\theta}{2} )$

7 $\frac{1-\text{cos}\theta}{2} =\text{sin}^2(\frac{\theta}{2} )$

8 $\pm \sqrt{\frac{1-\text{cos}\theta}{2} }=\text{sin}(\frac{\theta}{2} )$

There is a mistake in step 6.

Therefore, Option (3) will be the answer.

3 0

3 years ago

What is the slope of the line [lmk asap]

Viefleur [7K]

6/6 but it simplifies to 1

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3 years ago

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11. Suppose a force F varies as the product of two masses, m and M, inversely as

almond37 [142]

Answer:

$k = 6.74 * 10^{-5}$

Step-by-step explanation:

Given

$F\ \alpha\ \frac{m * M}{r^2}$ --- The variation

$F = 675; m = 125; M = 225; r = 0.0530$

Required

Determine the constant of proportionality (k)

$F\ \alpha\ \frac{m * M}{r^2}$

Express as an equation

$F = k\frac{m * M}{r^2}$

Multiply both sides by $r^2$

$Fr^2 = km * M$

Make k the subject

$k = \frac{Fr^2}{m * M}$

Given that: $F = 675; m = 125; M = 225; r = 0.0530$

We have:

$k = \frac{675* 0.0530^2}{125 * 225}$

$k = \frac{1.896075}{28125}$

$k = 0.000067416$

This can be represented as:

$k = 6.74 * 10^{-5}$

5 0

3 years ago