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3 years ago

Least common dominator for 12

2 answers:

6 0

The Answer Is 1, But One More Higher Would Be 2, Because 1 And 2 Are The Lowest Numbers That Go Into 12 Evenly. But There Is 3 And 4 That Go Into 12 Evenly, But 1 Is The Lowest

Debora [2.8K]3 years ago

4 0

You need multiple numbers to answer this. Please tell me this in more detail

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Need fast help

kumpel [21]

I don't know what a radicals is and I can't really show my work cuz I just do it all in my head but I'll solve it for you.

A) (2)(x^2-5x-4) this one can't be simplified anymore unless you use the quadratic formula which I'm too lazy to do

B) (2x-1)(2x-5)
X=1/2 or 5/2

6 0

3 years ago

Can someone please help me with number 17

taurus [48]

Make two parallel lines then make a line going through N but stop before M

4 0

3 years ago

According to national data, 5.1% of burglaries are cleared with arrests. A new detective is assigned to six different burglaries

blagie [28]

Answer:

26.95% probability that at least one of them is cleared with an arrest

Step-by-step explanation:

For each burglary, there are only two possible outcomes. Either it is cleared, or it is not. The probability of a burglary being cleared is independent of other burglaries. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5.1% of burglaries are cleared with arrests.

This means that $p = 0.051$

A new detective is assigned to six different burglaries.

This means that $n = 6$

What is the probability that at least one of them is cleared with an arrest?

Either none are cleared, or at least one is. The sum of the probabilities of these events is 100% = 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$

Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.(0.051)^{0}.(0.949)^{6} = 0.7305$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7305 = 0.2695$

26.95% probability that at least one of them is cleared with an arrest

8 0

3 years ago

Can somebody explain this to me?

hram777 [196]

First we will go to the section that lists that students that like hotdogs. 76 students out of 150 like hotdogs. Out of those 76 students, which of them like burgers?
32 students like hotdogs and burgers. 32/76 is equal to .421..., which when multiplied by 100 is equal to approximately 42.1%. We found the conditional frequency, or the column frequency. The correct answer is C.

7 0

3 years ago

For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The

Tema [17]

Answer:

Number of cheaper dresses sold is 35

Number of expensive dresses sold is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of expensive dresses = $140

Total cost of the dresses = $5250