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2 years ago

Identifying a constant of variation question R= ?

Mathematics

1 answer:

jek_recluse [69]2 years ago

4 0

Pressure and Volume are inversely related as:

$P= \frac{R}{V}$

We can also write it as:

$PV=R$

R is the constant of proportionality. Using the first row of given table, we can write:

$2(4.155)=R \\ \\ 
R=8.31$

Thus, the value of R, the universal gas constant is 8.31

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I need help answering this question. Any ideas on what it could be?

Lesechka [4]

Is this for a test/exam?

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2 years ago

A circle has a radius of 2.6 centimeters.What is the circumference,in centimeters,of the circle?

Tju [1.3M]

37.699cm

Hope this helped!

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3 years ago

Read 2 more answers

Describe the steps you can use to find an average of fractional amounts.

oksano4ka [1.4K]

Add up the fractional amounts and divide them by however many amounts there are..........

eg.

Step 1:Add the fractions
1/6 + 5/8 +3/4
(find the LCD)
1/6 + 5/8 + 3/4 = 4/24 + 15/24 + 18/24 = 37/24

Step 2: Divide the sum by the number of numbers in the set
37/24 ÷ 3= 37/24 ÷ 3/1= 37/24 X 1/3= 37/72

<span>So the mean (average) is 37/72</span>

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3 years ago

What is the value of y when y=10 and 1/4x+10-2y=3y

german

x=160 hope i helped

8 0

3 years ago

Let X represent the full height of a certain species of tree. Assume that X has a normal distribution with a mean of 137.1 ft an

Rama09 [41]

Answer:

0.0668 = 6.68% probability that the height of a randomly selected tree is as tall as mine or shorter.

0.0228 = 2.28% probability that the full height of a randomly selected tree is at least as tall as hers.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 137.1, \sigma = 3.2$

A tree of this type grows in my backyard, and it stands 132.3 feet tall. Find the probability that the height of a randomly selected tree is as tall as mine or shorter.

This is the pvalue of Z when X = 132.3. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{132.3 - 137.1}{3.2}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

0.0668 = 6.68% probability that the height of a randomly selected tree is as tall as mine or shorter.

My neighbor also has a tree of this type growing in her backyard, but hers stands 143.5 feet tall. Find the probability that the full height of a randomly selected tree is at least as tall as hers.

This is 1 subtracted by the pvalue of Z when X = 143.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{143.5 - 137.1}{3.2}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that the full height of a randomly selected tree is at least as tall as hers.

7 0

3 years ago