Need help not good with geometry

Mathematics

2 answers:

Alenkasestr [34]2 years ago

6 0

I think the answer is: 225.585

miv72 [106K]2 years ago

3 0

Just put "A" yeah "A" then yeah

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Determine in which quadrant the product of 5(cos3pi/8 + isin 3pi/8) and sqrt 2(cos pi/12 + sin pi/12) lies.

ohaa [14]

When you multiply two complex numbers given in polar form, the argument of the product is the sum of the arguments of the factors. Meanwhile, the modulus of the product is the product of the moduli of the factors.

In this case, you'd have

$\dfrac{3\pi}8+\dfrac\pi{12}=\dfrac{11\pi}{24}$

and the modulus would simply be $5\sqrt2$ . Since

$\dfrac{11\pi}{24}$

we would expect the final product to fall in the first quadrant.

6 0

2 years ago

Let f(x)=2x2−8 .

MrRa [10]

Move down c units means minus 2 from whole function

f(x) moved down 2 units means f(x)-2
so

f(x)-2=2x²-8-2
f(x)-2=2x²-10

g(x)=2x²-10

3 0

2 years ago

Read 2 more answers

Can anyone answer this

erik [133]

Answer:

Step-by-step explanation:

1. 10² + 7² = x²

149 = x²

x = √149

2. x² + 19² = 21²

x² = 21² - 19² = 80

x = √80 = 4√5

3. x² + 16² = 27²

x² = 27² - 16² = 473

x = √473

4. 5.3² + 12.8² = x²

191.93 = x²

x = √191.93

5. 9² + 20² = x²

481 = x²

x = √481

6. 31 = x + 2√(19²-17²) = x + 2·6√2 = x + 12√2

x = 31 - 12√2

5 0

2 years ago

The sum of two polynomials is –yz2 – 3z2 – 4y + 4. If one of the polynomials is y – 4yz2 – 3, what is the other polynomial? –2yz

marishachu [46]

The first polynomial is $y -4yz^2-3$ and let the second polynomial be P(y,z).

If the sum of two polynomials is $-yz^2-3z^2-4y+4$ , then $y-4yz^2-3+P(y,z)=-yz^2-3z^2-4y+4$ .

Take the first polynomial from the left side to the right side:

$P(y,z)=-yz^2-3z^2-4y+4 -(y-4yz^2-3),\\ P(y,z)=-yz^2-3z^2-4y+4 -y+4yz^2+3,\\ P(y,z)=3yz^2-3z^2-5y+7$ .

Answer: the second polynomial is $3yz^2-3z^2-5y+7$ .