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Alexxx [7]
3 years ago
11

What is the height of a parallelogram with base 6 meters and an area of 90 square meters​

Mathematics
1 answer:
bearhunter [10]3 years ago
5 0

Step-by-step explanation:

Given

In a parallelogram

base (b) = 6 meters

Area of parallelogram (A) = 90 m²

height (h) = ?

We know

A = b * h

90 = 6 * h

h = 90 / 6

h = 15 meters.

Hope it will help :)

You might be interested in
Which expression represents the ratio of the difference of the two means to Sidney's mean absolute deviation
prohojiy [21]

Answer:

The ratio of the difference of the two means to Sidney's mean absolute deviation = \frac{4}{3.28} = 1.2195

Step-by-step explanation:

P.S - The exact question is -

Given - The means and mean absolute deviations of Sidney’s and Phil’s grades are shown in the table below.

                                       Sidney’s Grades           Phil’s Grades

Mean                                     82                                    78

Mean Absolute Deviation      3.28                                 3.96

To find - Which expression represents the ratio of the difference of the two means to Sidney’s mean absolute deviation?

Proof -

Given that Mean of Sidney Grades = 82

                 Mean of Phil's   Grades = 78

So,

The difference of two means = 82 - 78 = 4

Also,

Given, Mean Absolute Deviation of Sydney = 3.28

Now,

The ratio of the difference of the two means to Sidney's mean absolute deviation = \frac{4}{3.28} = 1.2195

4 0
3 years ago
A recipe calls for 32 ounces of orange juice. How many cups of juice would you need for the recipe?
Andru [333]
The answer to your question is that there are 32 ounces in 4 cups
5 0
3 years ago
Read 2 more answers
How do i do these fractions by 1/2?
Svetlanka [38]
I need to see the directions
4 0
3 years ago
Ez pls help i will give extra points
My name is Ann [436]

Answer:

25.4

Step-by-step explanation:

1/3 ( 2.55+.75) +3* 8.1

Using pemdas, parentheses first

1/3 ( 3.3) +3* 8.1

Then multiply

1.1 + 24.3

Then add

25.4

7 0
3 years ago
Suppose $p(x)$ is a monic cubic polynomial with real coefficients such that $p(3-2i)=0$ and $p(0)=-52$. determine $p(x)$ (in exp
Maslowich

If p(3-2i)=0, then complex number 3-2i is a root of cubic polynomial.

If polynomial has real coefficients, then conjugated 3+2i is also a root of polynomial.

Then the polynomial will be of a form

p(x)=(x-(3-2i))(x-(3+2i))(x-a).

Since p(0)=-52, then

-52=(0-(3-2i))(0-(3+2i))(0-a),\\ \\-52=(2i-3)(3+2i)a,\\ \\-52=(4i^2-9)a,\\ \\-52=(-4-9)a,\\ \\-13a=-52,\\ \\a=4.

Therefore,

p(x)=(x-(3-2i))(x-(3+2i))(x-4),\\ \\p(x)=(x^2-6x+13)(x-4),\\ \\p(x)=x^3-10x^2+37x-52.

3 0
3 years ago
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