Answer:
16716p
Step-by-step explanation:
28 x 150 x ( 5 x 8 ) - 30
Amount of Interest=7152-6400=752=I
- Principal=6400=P
- Rate of interest=6%=R
- Time=T=?
We know
![\boxed{\sf I=\dfrac{PRT}{100}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20I%3D%5Cdfrac%7BPRT%7D%7B100%7D%7D)
![\\ \sf\longmapsto T=\dfrac{PR}{100I}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20T%3D%5Cdfrac%7BPR%7D%7B100I%7D)
![\\ \sf\longmapsto T=\dfrac{6400(6)}{100(752)}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20T%3D%5Cdfrac%7B6400%286%29%7D%7B100%28752%29%7D)
![\\ \sf\longmapsto T=\dfrac{38400}{75200}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20T%3D%5Cdfrac%7B38400%7D%7B75200%7D)
![\\ \sf\longmapsto T\approx 0.5year](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20T%5Capprox%200.5year)
![\\ \sf\longmapsto T\approx 6months](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20T%5Capprox%206months)
The answer to the first question is 8 boxes of ice cream bars.
The answer to the second question is 78 staff members.
The total number of strawberries on the farm is approximately 107
<h3>Total strawberries</h3>
The total number of strawberries on the farm can be solved by evaluating the expression (4 over 3)2 ⋅ 40.
Evaluation is the completion of a mathematical operation.
Number of strawberries on the farm = (4 over 3)2 ⋅ 40
= (4/3)2 × 40
= 8/3 × 40
= (8 × 40) / 3
= 320/3
= 106.6666666666666
Approximately,
Number of strawberries on the farm = 107
A strawberry is a sweet, usually red, edible fruit of certain plants of the genus Fragaria.
A farm is a piece of land where plants are cultivated and animals are reared by the farmer.
Therefore, the total number of strawberries on the farm is approximately 107.
Learn more about total:
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Answer: 0.4
Step-by-step explanation:
Given: Cumulative exponential distribution:
![P(x](https://tex.z-dn.net/?f=P%28x%3Ck%29%3D1-e%5E%7B%5Cfrac%7B-x%7D%7Bk%7D%7D)
As per given,
![P(x](https://tex.z-dn.net/?f=P%28x%3C2%29%3D1-e%5E%7B%5Cfrac%7B-2%7D%7Bk%7D%7D%3D0.381%5C%5C%5C%5C%5CRightarrow%5C%20e%5E%7B%5Cfrac%7B-2%7D%7Bk%7D%7D%3D1-0.381%5C%5C%5C%5C%5CRightarrow%5C%20e%5E%7B%5Cfrac%7B-2%7D%7Bk%7D%7D%3D0.619%5C%5C%5C%5C%5CRightarrow%5C%20%7B%5Cfrac%7B-2%7D%7Bk%7D%7D%3D%5Cln%280.619%29%20%5C%20%5C%20%5C%20%5B%5Ctext%7BTaking%20natural%20log%20on%20both%20sides%20%7D%5D%5C%5C%5C%5C%5CRightarrow%5C%20%7B%5Cfrac%7B-2%7D%7Bk%7D%7D%3D-0.47965%5C%5C%5C%5C%5CRightarrow%5C%20k%3D%5Cdfrac%7B2%7D%7B0.47965%7D%5C%5C%5C%5C%5CRightarrow%5C%20k%3D4.17)
![P(0.5 < X < 3) \\\\=P(X](https://tex.z-dn.net/?f=P%280.5%20%3C%20X%20%3C%203%29%20%5C%5C%5C%5C%3DP%28X%3C3%29-P%28X%3C0.5%29%20%5C%5C%5C%5C%3D%281-e%5E%7B-%5Cfrac%7B3%7D%7B4.17%7D%7D%29-%281-e%5E%7B-%5Cfrac%7B0.5%7D%7B4.17%7D%7D%29%20%5C%5C%5C%5C%3De%5E%7B-%5Cfrac%7B0.5%7D%7B4.17%7D%7D-e%5E%7B-%5Cfrac%7B3%7D%7B4.17%7D%7D%5C%5C%5C%5C%3D%200.4)
Hence, the required probability = 0.4