The maximized value of the function is (c) 119/2
<h3>Maximization problem</h3>
Maximization problems are used to determine the optimal solution of a linear programming model
<h3>Objective function</h3>
The objective function is given as:
<h3>Constraints</h3>
The constraints are given as:
<h3>Graph</h3>
See attachment for the graph of the constraints
From the graph, the optimal solution is: (2.83, 2.83)
So, the maximized value is:
Approximate
Rewrite as a fraction
Hence, the maximized value of the function is (c) 119/2
Read more about maximization problem at:
brainly.com/question/16826001
Answer:
y=(7±√89)/-4
Step-by-step explanation:
y=(-b±√b^2 -4ac)/2a
Rewrite given equation in quadratic form so it is -2y-7y+5=0
Then, in formula, sub -2 for a, -7 for b, and 5 for c
y=-(-7)±√(-7)^2 -4(-2)(5)/2(-2)
When you multiply that out you get
7±√49-(-40)/-4
The next step is the answer given above
If you need the answer not in sq rt form, it is y=-4.1085 and y=0.0608
Answer: The required exponential model is 
Step-by-step explanation:
Since we have given that
Initial cases = 1804
Rate of growth = 4%
Since it is increasing exponentially,
So, it becomes,
Here, a = 1804
b = 
So, it becomes,
Hence, the required exponential model is
2k = 25
Divide 2 on each side
k = 12.5
Each pizza would cost $12.50
Hope this helps!
