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Mrrafil [7]
3 years ago
9

A trapezoid is a quadrilateral with exactly one pair of parallel sides.

Mathematics
2 answers:
qaws [65]3 years ago
7 0

Answer:

true

Step-by-step explanation:

Sedaia [141]3 years ago
4 0

Answer: A. TRUE

Step-by-step explanation:

If it has two pairs of parallel sides it is a parallelogram, but parallelograms are also trapezoids in the same way that dogs are also mammals. A parallelogram has two pairs of congruent sides.

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1 .what is the value of x?<br> 2 .what is the value of y ?
kifflom [539]

Answer:

ans of y is 3 because 12-3=9

8 0
3 years ago
PLS , help me asap :(( , im so frustrated , idk how to do these :c
kolezko [41]

Answer:

y intercept = 5

Step-by-step explanation:

In analytic geometry, using the common convention that the horizontal axis represents a variable x and the vertical axis represents a variable y, a y-intercept or vertical intercept is a point where the graph of a function or relation intersects the y-axis of the coordinate system. As such, these points satisfy x = 0.

6 0
3 years ago
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Jodi bought a new sofa for $1,430, including finance charge. She made down payment of $130 and paid off the balance in 18 months
m_a_m_a [10]
The finance Charge would be $140. you would multiply 18 by 80 and then add the 130 and take that number and subtract the 1,430
6 0
3 years ago
Which of the following is the absolute value of 6 - 3/
Nina [5.8K]

Answer:

3

Step-by-step explanation:

| 6-3|

Find the value inside the absolute value signs

6-3 = 3

| 3|

Means take the non negative value

|3| = 3

5 0
3 years ago
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What are the next 3 numbers in this pattern of integers -2, -1, -1, 0, -1, 1, -2
sashaice [31]

Answer:

The next 3 numbers to the given pattern of integers is -2,-1,-1,0,-1,1,-2 are 3,-5,8

Step-by-step explanation:

Given pattern of integers is -2,-1,-1,0,-1,1,-2

To find their next 3 numbers of the given pattern :

Let a_{1}=-2

a_{2}=-1

a_{3}=a_{1}-a_{2}

=-2-(-1)

=-2+1

Therefore a_{3}=-1

a_{4}=a_{2}-a_{3}

=-1-(-1)

=-1+1

Therefore a_{4}=0

Similarly we have a_{5}=-1 ,a_{6}=1 ,a_{7}=-2

The general form to the given pattern is

a_{n}=a_{n-2}+a_{n-1}  for n={\{1,2,3,4,5,6,7,8,9,10}\}

Therefore to find the a_{8},a_{9},a_{10}

Put n=8 in a_{n}=a_{n-2}-a_{n-1}

a_{8}=a_{8-2}-a_{8-1}

=a_{6}-a_{7}

=1-(-2)

a_{8}=3

Put n=9 in a_{n}=a_{n-2}-a_{n-1}

a_{9}=a_{9-2}-a_{9-1}

=a_{7}-a_{8}

=-2-(3)

a_{9}=-5

Put n=10 in a_{n}=a_{n-2}-a_{n-1}

a_{10}=a_{10-2}-a_{10-1}

=a_{8}-a_{9}

=3-(-5)

a_{10}=8

Therefore the next 3 numbers are 3,-5,8

4 0
3 years ago
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