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lutik1710 [3]
3 years ago
7

I need to find X thank you

Mathematics
1 answer:
Pani-rosa [81]3 years ago
8 0
I don't see anything
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Consider the matrix shown below:
balu736 [363]

Answer:

Its Not C or B, tried em and got em wrong

Step-by-step explanation:

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3 years ago
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Find m&lt; A<br> inscribed angles and arcs
never [62]

Answer: 115 degrees

Step-by-step explanation:

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2 years ago
Determine whether the set of vectors is a basis for ℛ3. Given the set of vectors , decide which of the following statements is t
schepotkina [342]

Answer:

(A) Set A is linearly independent and spans R^3. Set is a basis for R^3.

Step-by-Step Explanation

<u>Definition (Linear Independence)</u>

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

<u>Definition (Span of a Set of Vectors)</u>

The Span of a set of vectors is the set of all linear combinations of the vectors.

<u>Definition (A Basis of a Subspace).</u>

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors  A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right) , we are to decide which of the given statements is true:

In Matrix A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right) , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. R^3 has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans R^3.

Therefore Set A is linearly independent and spans R^3. Thus it is basis for R^3.

8 0
3 years ago
Calculate the volume of the cylinder:<br> 10 cm<br> 6 cm
barxatty [35]

Answer:

60

Step-by-step explanation:

10 ×6

that is the simple answer to your question

7 0
2 years ago
Which of the following gives a single solution of the |x+3|- 2
topjm [15]

Answer:

x=-1

Step-by-step explanation:

given \left | x+3 \right |-2=0

\left | x+3 \right |=2

x+3=+2

x=-1,     also,  x+3=-2

                    x=-2-3=-5

hence x=-1 , -5 answer

6 0
3 years ago
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