Hey!
2x + 4y = 3x + 3y = 13
2x + 4y = 13 ------------ ( 1 )
3x + 3y = 13 -------------- ( 2 )
Now, we will need to eliminate one type of the term , let us eliminate the x terms
Let us multiply the first equation with 3 and the second equation with 2
3 ( 2x + 4y ) = 3 ( 13 )
2 ( 3x + 3y ) = 2 ( 13 )
................................................................................................................................................
6x + 12y = 39 ----------------- ( 1 )
6x + 6y = 26 ---------------------- ( 2 )
Now, let us subtract the second equation from the first equation
6x + 12y = 39
-6x - 6y = - 26
.........................................
6y = 13
y = 13 / 6
...........................................
Now substitute the value of ' y ' and we can get the value of ' x '
I will take 3x + 3y = 13
3x + ( 3 ) ( 13 / 6 ) = 13
3x + 13 / 2 = 13
3x = 13 - 13/2
LCM = 2
3x = 26 - 13 / 2
3x = 13 / 2
x = 13/2 / 3
x = 13/2 × 1/3
x = 13/6
Hope my answer helps!
