Answer:
v = 80 mph
Step-by-step explanation:
Given that,
The distance from Wakefield to London is 180 miles.
The train travels this distance in 2 hours 15 minutes.
We need to find the average speed of the train. The average speed of the train is equal to the total distance covered divided by the time taken.
![v=\dfrac{d}{t}\\\\v=\dfrac{180\ miles}{(2+\dfrac{15}{60})\ h}\\\\v=80\ mph](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7Bd%7D%7Bt%7D%5C%5C%5C%5Cv%3D%5Cdfrac%7B180%5C%20miles%7D%7B%282%2B%5Cdfrac%7B15%7D%7B60%7D%29%5C%20h%7D%5C%5C%5C%5Cv%3D80%5C%20mph)
So, the required average speed of the train is 80 mph.
Answer:
System utilization = 0.7 or 70%
Step-by-step explanation:
Given arrival rate of customer = 15 customer/Hour
Servie rate =
Now, use the below formula to find the system utilization.
System utilization =
System utilization =
System utilization =
System utilization = 0.7 or 70%
Answer:
I think it is 100000 0 value is more than ever number
1
Ive got no idea but if this is the only info u have then im assuming 1
Answer:
(-1 (3 y + 17))/2
Step-by-step explanation:
Simplify the following:
y/4 - (1 + 3/4) y - 12 + 1/2 + 1 + 2
Put 1 + 3/4 over the common denominator 4. 1 + 3/4 = 4/4 + 3/4:
y/4 - 4/4 + 3/4 y - 12 + 1/2 + 1 + 2
4/4 + 3/4 = (4 + 3)/4:
y/4 - (4 + 3)/4 y - 12 + 1/2 + 1 + 2
4 + 3 = 7:
y/4 - 7 y/4 - 12 + 1/2 + 1 + 2
Put each term in y/4 - (7 y)/4 - 12 + 1/2 + 1 + 2 over the common denominator 4: y/4 - (7 y)/4 - 12 + 1/2 + 1 + 2 = y/4 - (7 y)/4 - 48/4 + 2/4 + 4/4 + 8/4:
y/4 - (7 y)/4 - 48/4 + 2/4 + 4/4 + 8/4
y/4 - (7 y)/4 - 48/4 + 2/4 + 4/4 + 8/4 = (y - 7 y - 48 + 2 + 4 + 8)/4:
(y - 7 y - 48 + 2 + 4 + 8)/4
Grouping like terms, y - 7 y - 48 + 2 + 4 + 8 = (y - 7 y) + (4 + 2 + 8 - 48):
((y - 7 y) + (4 + 2 + 8 - 48))/4
y - 7 y = -6 y:
(-6 y + (4 + 2 + 8 - 48))/4
4 + 2 + 8 - 48 = -34:
(-34 - 6 y)/4
Factor -2 out of -6 y - 34:
(-2 (3 y + 17))/4
The gcd of -2 and 4 is 2, so (-2 (3 y + 17))/4 = ((2 (-1)) (3 y + 17))/(2×2) = 2/2×(-(3 y + 17))/2 = (-(3 y + 17))/2:
Answer: (-1 (3 y + 17))/2