Answer: 912
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Work Shown:
The starting term is a1 = 3. The common difference is d = 5 (since we add 5 to each term to get the next term). The nth term formula is
an = a1+d(n-1)
an = 3+5(n-1)
an = 3+5n-5
an = 5n-2
Plug n = 19 into the formula to find the 19th term
an = 5n-2
a19 = 5*19-2
a19 = 95-2
a19 = 93
Add the first and nineteenth terms (a1 = 3 and a19 = 93) to get a1+a19 = 3+93 = 96
Multiply this by n/2 = 19/2 = 9.5 to get the final answer
96*9.5 = 912
I used the formula
Sn = (n/2)*(a1 + an)
where you add the first term (a1) to the nth term (an), then multiply by n/2
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As a check, here are the 19 terms listed out and added up. We get 912 like expected.
3+8+13+18 +23+28+33+38 +43+48+53+58 +63+68+73+78 +83+88+93 = 912
There are 19 values being added up in that equation above. I used spaces to help group the values (groups of four; except the last group which is 3 values) so it's a bit more readable.
Answer:
The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for the average using the finite correction factor is:
The information provided is:
The critical value of <em>z</em> for 95% confidence level is,
<em>z</em> = 1.96
Compute the 95% confidence interval for the average number of years until the first major repair as follows:
Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).
Answer:
x = 15
Step-by-step explanation:
20^2 + x^2 = 25^2
400 + x^2 = 625
subtract each side 400
it results to 225
square root 225, to equals this -->
X = 15
Answer:
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Step-by-step explanation:
