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3 years ago

Plis i need help whit this questionss

Mathematics

1 answer:

zmey [24]3 years ago

8 0

Question 1: x+2 = 8 doesn't belong in the given equations.

Question 2: The possible values for y are 0,1 and 2

Step-by-step explanation:

Question: Which one doesn't belong?

We will solve each equation one by one to get which equation doesn't belong with others

So,

$x+4 = -2\\x+4-4 = -2-4\\x = -6$

$x+5 = -1\\x+5-5 = -1-5\\x = -6$

$x+2 = 8\\x+2-2 = 8-2\\x = 6$

$3-x=9\\3-x-3 = 9-3\\-x = 6\\x = -6$

Hence,

x+2 = 8 doesn't belong in the given equations.

Question 2:

Given equation is:

$x+y = 5$

It is given that the values of x will be greater than 2 and less than 6 so values of x can be 3,4 and 5

So,

$3+y = 5\\y = 5-3\\y = 2\\\\4+y = 5\\y = 5-4\\y = 1\\\\5+y = 5\\y = 5-5\\y = 0$

Hence,

The possible values for y are 0,1 and 2

So,

x+2 = 8 doesn't belong in the given equations.

The possible values for y are 0,1 and 2

Keywords: Linear equation, variables

Learn more about linear equations at:

#LearnwithBrainly

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Step-by-step explanation:

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3 years ago

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Could someone pls send me an example of using the substitution method in algebra?

Elden [556K]

Answer:

in this method a variable is expressed in terms of another variable from one equation and it is substituted in remaining equation.

Step-by-step explanation:

solve:x+2y=9 and 3x-y=13.

x+ 2y=9…be the first equation

3x-y=13…be the second equation

from first equation

x=9-2y…be the third equation substituting value of x from third equation in second equation, we get

3(9-2y)-y=13

or, 27-6y-y=13

or, y=2

now,

substituting value of y in third equation, we get,

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3 years ago

Define a variable write an equation and solve the problem. the width of a rectangle is 3 meters more than one-fourth its length.

sweet [91]

Let's assume

length of rectangle is L

width of rectangle is W

the width of a rectangle is 3 meters more than one-fourth its length

so,

$W=3+\frac{1}{4} L$

the perimeter is 10 meters more than twice its length

we know that

perimeter =2(L+W)

so, we get

$2(L+W)=10+2L$

now, we can simplify it

$2L+2W=10+2L$

subtract both sides by 2L

$2L+2W-2L=10+2L-2L$

$2W=10$

$W=5$

now, we can find L

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subtract both sides 3

$5-3=3-3+\frac{1}{4} L$

$2=\frac{1}{4} L$

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length of rectangle is 8 meter

width of rectangle is 5 meter ............Answer

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3 years ago

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3 years ago

A recursive rule for an arithmetic sequence is a₁=4;a_n=a_(n−1)−3 .

steposvetlana [31]

The explicit formula of the arithmetic sequence:

$a_n=a_1+(n-1)d$

d - common difference

We have the recursive formula of an arithmetic sequence:

$\left\{\begin{array}{ccc}a_1=4\\a_n=a_{n-1}-3\end{array}\right$

Therefore we have:

$a_1=4,\ d=-3$

Substitute:

$a_n=4+(n-1)(-3)=4-3n+3=7-3n$

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3 years ago

Plis i need help whit this questionss​

Plis i need help whit this questionss