A line passes through the point (4, –2) and has a slope of One-half.

Mathematics

2 answers:

Keith_Richards [23]3 years ago

8 0

Answer:

a = -6

Step-by-step explanation:

The given line in point-slope form is y + 2 = (1/2)(x - 4).

Replacing x with -4 yields y + 2 = (1/2)(-4 - 4) = (1/2)(-8)

Then y + 2 = -4, and so y = -6, or a = - 6.

Gemiola [76]3 years ago

4 0

Answer:

The Answer would be A= -6

Step-by-step explanation:

The given line in point-slope form is y + 2 = (1/2)(x - 4).

Replacing x with would be result in y + 2 = (1/2)(-4 - 4) = (1/2)(-8)

.Then y + 2 = -4, which would mean that y = -6, or a = - 6 would be the answer to this equation.

Hope this helps. :)

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Step-by-step explanation:

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3 years ago

Chords AB and CD intersect at point E, AE = 10, EB = 4, and CE = 8. Therefore, ED =

Genrish500 [490]

So here is how we are going to find out what is ED.
Based on the given figure, it states that, AE is 10, and EB is 4 and CE is 8.
So, <span>(AE/CE)=(ED/EB)
10/8 = ED/4 <<multiply both sides by the common denominator which is 8 and the result would be:
80/8 = 8ED/4
10 = 2ED <<divide both sides by 2 and we get
ED = 5.
Therefore, the measurement of ED is 5.
Hope this answer helps. Let me know if you need more help next time!</span>

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3 years ago

Read 2 more answers

Two factories I and II produce phones for brand ABC. Factory I produces 60% of all ABC phones, and factory II produces 40%. 10%

denpristay [2]

Answer:

0.3721 or 37.21%

Step-by-step explanation:

P(I) = 0.60; P(II) = 0.40;

P(not defective I) = 0.90; P(not defective II) = 0.80

The probability that the phone came from factory II, given that is not defective, is determined by the probability of a phone from factory II not being defective divided by the probability of a phone not being defective.

$P(II|not) = \frac{P(II)*P(not_{II})}{P(II)*P(not_{II})+P(I)*P(not_{I})}\\P(II|not) = \frac{0.40*0.80}{0.40*0.80+0.60*0.90}\\ P(II|not) =0.3721 = 37.21\%$