If the polynomial is of the form x^2+bx+c (ie., no factor in front of the x^2!!) then you can look for numbers that add up to b and multiply to c.
So in this case: what two numbers, when added, give -2 and when multiplied, give 1? A little trial and error gives you -1 and -1.
So the factorization is (x-1)(x-1). This is zero for x=1. There is only one zero.
Answer:
5-Cy/r = d
Step-by-step explanation:
C=r(5-d)/y
Multiply each side by y
Cy=r(5-d)/y *y
Cy=r(5-d)
Divide each side by r
Cy/r=r(5-d)/r
Cy/r=(5-d)
Subtract 5 from each side
Cy/r - 5 = 5-d-5
Cy/r - 5 = -d
Multiply by -1
-Cy/r + 5 = d
5-Cy/r = d
<h3>
Answer: b+5a</h3>
Explanation:
The commutative property of addition is where we can add two numbers in any order.
The general equation is x+y = y+x
A more concrete example would be something like 2+3 = 3+2 since both sides simplify to 5.
For 5a+b, it is the same as b+5a. We swap the two terms.
