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Lapatulllka [165]
3 years ago
15

Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling. Abha collected 178

more cans than Shane did. Write an inequality to determine the number of cans, S, that Shane could have collected.
Mathematics
1 answer:
Katarina [22]3 years ago
4 0

Answer:

2x+178\geq 2000

Step-by-step explanation:

Let, the number of cans collected by Shane = x.

So, the number of cans collected by Abha = x + 178.

Since, at least 2000 cans are required to be collected.

Thus, we have the inequality,

Number of cans by Shane + Number of cans by Abha ≥ 2000.

i.e. x+(x+178)\geq 2000

i.e. 2x+178\geq 2000

Thus, the required inequality is 2x+178\geq 2000.

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2 years ago
In ΔJKL, l = 860 inches, j = 920 inches and ∠K=126°. Find ∠L, to the nearest degree.
fomenos

Answer:

26

Step-by-step explanation:

JKL= ABC,  jkl=abc

1.) use law of sines to find k.

c^{2} =a^{2} +b^{2} -2abCosC    

c=\sqrt{920^{2} +860^{2} -2(920)(860)cos(126) } = 1586.225515

2.) use law of cosines to find L

\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}  

plug in for b and c:  \frac{860}{sinB} =\frac{1586.225515}{sin126}

cross multiply: \frac{1586.23sinB}{1586.23} =\frac{860sin126}{1586.23}

sinB= 0.4386227612\\B=sin^-1(0.4386227612)= 26.01604086\\

L=26

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3 years ago
Use the discriminant to determine the number and type of solutions for the following equation.
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2 years ago
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