Please choose any two and help me answer i will be very grateful and will mark you brainliest

Mathematics

2 answers:

Nataly_w [17]3 years ago

5 0

Answers:

<u>Top Yellow:</u> 2(n+7) = 13

<u>Bottom Red</u>: 5(n-2) = 4

Step-by-step explanation:

<u>Top Yellow Example:</u> 2 times the sum of the number x and 7 is 13. Use words in the sentence to replace them with mathematical symbols. Sum is equal to +, etc. 2(n+7) = 13 is your answer.

ehidna [41]3 years ago

4 0

Answer:

18 and 20, 4

Step-by-step explanation:

Math reasoning 1:

Set the first number as x and the other one as x+2 because it is a consecutive even number.

x+x+2=38

2x=36

x=18

18+2=20

The 2 consecutive numbers are 18 and 20

Problem solving 1:

Write out equation first, set the unknown number as x

5+x=9

x=4

You might be interested in

The price of an article with 15% VAT is Rs 920. What will be the excluding VAT?<br>Ans:800

Fantom [35]

Answer:

AOA

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Carl wants to plant a garden that is 1 1/2 yards long and has an area of 3 1/2 yd.² how wide should the Garden be

lesya692 [45]

L= length= 1 1/2 yards
A= area= 3 1/2 yards^2
w= width

Area= length * width
plug in numbers you know
3 1/2= (1 1/2)(w)
convert to improper fractions
(3*2+1)/2= ((1*2+1)/2)(w)
7/2= 3/2w
divide both sides by 3/2
7/2 ÷ 3/2= w
to divide fractions, multiply by the reciprocal/inverse of 3/2
7/2 * 2/3= w
(7*2)/(2*3)= w
14/6= w
reduce by 2
7/3= width as improper fraction
OR
2 1/3= width as mixed fraction

ANSWER: The width should be 2 1/3 yards wide (or 7/3 yards wide).

Hope this helps! :)

8 0

3 years ago

Help! How would I solve this trig identity?

NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

$sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}$

Then the identity can be rewritten as:

$sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\$

Now we can multiply both sides by cos⁴(x) to get:

$\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)$