Answer:
![531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6](https://tex.z-dn.net/?f=531441a%5E6-3542940a%5E5b%2B9841500a%5E4b%5E2-14580000a%5E3b%5E3%2B12150000a%5E2b%5E4-5400000ab%5E5%2B1000000b%5E6)
Step-by-step explanation:
1 n=0
1 1 n=1
1 2 1 n=2
1 3 3 1 n=3
1 4 6 4 1 n=4
1 5 10 10 5 1 n=5
1 6 15 20 15 6 1 n=6
This is where n is the exponent in
.
![(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6](https://tex.z-dn.net/?f=%28x%2By%29%5E6%3D1x%5E6%2B6x%5E5y%2B15x%5E4y%5E2%2B20x%5E3y%5E3%2B15x%5E2y%5E4%2B6xy%5E5%2B1y%5E6)
Now we want to expand:
or we we can rewrite as
.
Let's replace
with
and
with
in the expansion:
![(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6](https://tex.z-dn.net/?f=%28x%2By%29%5E6%3D1x%5E6%2B6x%5E5y%2B15x%5E4y%5E2%2B20x%5E3y%5E3%2B15x%5E2y%5E4%2B6xy%5E5%2B1y%5E6)
![((9a)+(-10b))^6](https://tex.z-dn.net/?f=%28%289a%29%2B%28-10b%29%29%5E6)
![=1(9a)^6+6(9a)^5(-10b)+15(9a)^4(-10b)^2+20(9a)^3(-10b)^3+15(9a)^2(-10b)^4+6(9a)(-10b)^5+1(-10b)^6](https://tex.z-dn.net/?f=%3D1%289a%29%5E6%2B6%289a%29%5E5%28-10b%29%2B15%289a%29%5E4%28-10b%29%5E2%2B20%289a%29%5E3%28-10b%29%5E3%2B15%289a%29%5E2%28-10b%29%5E4%2B6%289a%29%28-10b%29%5E5%2B1%28-10b%29%5E6)
Let's simplify a bit:
![=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6](https://tex.z-dn.net/?f=%3D9%5E6a%5E6-60%289%29%5E5a%5E5b%2B15%28-10%29%5E2%289%29%5E4a%5E4b%5E2%2B20%289%29%5E3%28-10%29%5E3a%5E3b%5E3%2B15%289%29%5E2%28-10%29%5E4a%5E2b%5E4%2B6%289%29%28-10%29%5E5ab%5E5%2B%28-10%29%5E6b%5E6)
![=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6](https://tex.z-dn.net/?f=%3D531441a%5E6-3542940a%5E5b%2B9841500a%5E4b%5E2-14580000a%5E3b%5E3%2B12150000a%5E2b%5E4-5400000ab%5E5%2B1000000b%5E6)
Answer:
(4) -1.
Step-by-step explanation:
First evaluate f(π/2) which is 2 * π/2 = π.
So g(f(π/2)) = g(π)
= cos π
= -1.
Answer:
![2.664 * 10^{7}](https://tex.z-dn.net/?f=2.664%20%2A%2010%5E%7B7%7D)
Step-by-step explanation:
Angles PQT and RQS are vertical angles and angles PQR and TQS are vertical angles.
angle PQS and TQR are straight angles
angles TQP and PQR form a linear pair. they are also adjacent by default. the other angles have these same features.
that should bout do it. hope it helped!
Answer and Step-by-step explanation:
First, solve for the volume of the sphere, then solve for the height of the cone using the volume of the sphere (which is said to be equal to the volume of the cone) and the radius given.
<u>Volume formula of Sphere</u>
V = ![\frac{4}{3} \pi r^2](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20r%5E2)
<u>Substitute 1 in for r</u>
= Volume
<u>Finding the Height of a Cone</u>
Volume formula for Cone: ![V = \pi r^2\frac{h}{3}](https://tex.z-dn.net/?f=V%20%3D%20%5Cpi%20r%5E2%5Cfrac%7Bh%7D%7B3%7D)
<u />
<u>Solve for </u><u><em>h</em></u>
Multiply both sides by 3, then divide by pi and r^2.
![h = \frac{3V}{\pi r^2}](https://tex.z-dn.net/?f=h%20%3D%20%5Cfrac%7B3V%7D%7B%5Cpi%20r%5E2%7D)
<u>Plug in the volume and the radius.</u>
![h = \frac{3(4.189)}{\pi (1)^2}](https://tex.z-dn.net/?f=h%20%3D%20%5Cfrac%7B3%284.189%29%7D%7B%5Cpi%20%281%29%5E2%7D)
<u>Simplify</u>
![h = \frac{12.567}{\pi }](https://tex.z-dn.net/?f=h%20%3D%20%5Cfrac%7B12.567%7D%7B%5Cpi%20%7D)
h ≈ 4
<u>4 is approximately the height.</u>
<u></u>
<u></u>
<u><em>#TeamTrees #PAW (Plant And Water)</em></u>