Answer:
a. 1965
b. 8 years
Step-by-step explanation:
For answers to questions like these it can work to consider the smallest possible dataset.
<h3>Dataset</h3>
For our purpose, consider the 9 years/values to be averaged to be ...
1, 2, 3, 4, 5, 6, 7, 8 ,9
<h3>Observations</h3>
a. The center value of the data set is 5. Its number is 5-1=4 more than the first one.
The first centered value is from the year 1961 +4 = 1965.
b. The 4 values at the beginning, and the 4 values at the end do not have a corresponding "average" value. That is, 4+4 = 8 values in the series are lost with respect to the number of average values.
8 years of values are lost.
In standard form, slope is always the negative of the x coefficient over the y coefficient.
If you dont want to have that memorized, you can use algebra to get the equation of the line into slope-intercept form (y=mx+b)
Set it equal to y
2x - 5y = 6
2x = 5y + 6
2x - 6 = 5y
(2/5)x - 6/5 = y
Now it is in slope intercept form. In slope intercept form, the coefficient multiplying with x is the slope of the line. Therefore, the slope equals 2/5.
Answer:
i
Step-by-step explanation:
Answer:
2/15
Step-by-step explanation:
If you graph it on a line, 2/15 will be the closest to 0.
