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melomori [17]
3 years ago
14

Joaquin is constructing the perpendicular bisector of AB. He opens his

Mathematics
2 answers:
vekshin13 years ago
9 0

Answer:

A

Step-by-step explanation:

The steps for constructing the perpendicular bisector is:

Step 1:

Open the compass more than half of the length of the segment AB and put it on point A and draw an arc across AB

Step 2:

Place the compass with the same width on point B and draw an arc across AB.

Step 3:

Place the ruler on the points above and below AB and draw a line.

Step 4:

The line is the perpendicualr bisector of the line segment AB ..

Hence, option A is the correct answer ..

kogti [31]3 years ago
3 0
<h2>Answer:</h2>

Option: A is the correct answer.

A.  Place the point of compass on point B and draw an arc across AB.

<h2>Step-by-step explanation:</h2>

The steps for constructing perpendicular bisector of line segment AB are as follows:

1. Draw a line segment AB.

2. Now, open the span of compass more than half the distance of AB and put the point of compass at A and draw arc across AB.

3. Now keeping the same span of compass, place the point of compass at B and draw an arc across AB.

4. Now, draw the line connecting the point of intersection of the two arcs.

5. The line so obtained is a perpendicular bisector of the line AB. and the point where the line meets AB is the mid-point of AB.

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(-3x+3y=-9)-(-3x+y=7)

-3x+3x+3y-y=-9-7

2y=-16

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Kittens weigh about 100 grams when born and gain 7 to 15 grams per day. If a kitten weighed 100 grams at birth and gained 8 gram
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First, start with an equation

100+8x= kittens weight

(X representing the days)

Since you’re trying to figure out the number of days it takes the kitten to triple it’s weigh you multiply it’s initial weight by 3 (100•3)

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Suppose that the given line has a slope of -2/3 and a y-intercept of (0,5/3). which of the following points is also a solution t
otez555 [7]

Answer:

From five given points it is find that points (1 , 1) and (4 , -1) will apply

Step-by-step explanation:

According to question,

Slop of line (m) = \frac{-2}{3}

And y-intercept is ( 0, \frac{5}{3})

So from above slope and points, the equation of line can be written as

y = mx + c

i.e \frac{5}{3} = \frac{-2}{3} x + c

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    \frac{5}{3} = 0 + c

Or, c = \frac{5}{3}

A) With points ( 5, \frac{5}{3} )

   At x = 5, y =\frac{-2}{3} (5) + \frac{5}{3}

            or, y = \frac{-10}{3} + \frac{5}{3}

            so, y = \frac{-5}{3}

Hence this points do not apply

B) With points ( 1 , 1 )

   At x = 1, y =  \frac{-2}{3} (1) +  \frac{5}{3}

      or,      y =  \frac{-2+5}{3}

      So,     y =  \frac{3}{3}

                y = 1

Hence this points will apply

C) With points ( 4 , -1 )

    At x = 4 , y =  \frac{-2}{3} (4) +  \frac{5}{3}

                    y =  \frac{-8+5}{3}

                    y =  \frac{-3}{3}

             So,  y= -1

Hence this points will apply

D) With points (-3 ,7)

    At x = - 3, y = \frac{-2}{3} (-3) +  \frac{5}{3}

                     y = \frac{14}{3}

 Hence this point will not apply

E) with points (0 , 0)

    At x 0,     y =  \frac{-2}{3} (0) +  \frac{5}{3}

               Or, y = 0 +  \frac{5}{3}

                     y =  \frac{5}{3}

Hence this point will not apply

∴ From above five given points it is find that points (1 , 1) and (4 , -1) apply

Answer

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