All categories

3 years ago

Consider the equation 3(-x+2)-1=5x-4

Mathematics

1 answer:

Gnom [1K]3 years ago

6 0

Answer:

9/8

Step-by-step explanation:

Step 1 :

(3 • (2 - x) - 1) - (5x - 4) = 0

Step 2 :

9 - 8x = 0

Step 3 :

3.1 Solve : -8x+9 = 0

Subtract 9 from both sides of the equation :

-8x = -9

Multiply both sides of the equation by (-1) : 8x = 9

Divide both sides of the equation by 8:

x = 9/8 = 1.125

One solution was found :

x = 9/8 = 1.125

You might be interested in

if the 300 inspected light bulbs represent 20% of an hour's total production of light bulbs, how many light bulbs are produced i

KIM [24]

Hi there!
So to get this we just need to multiply 300 by 5 because it is 1/5 of the hour work. 300 x 5 = 1500 light bulbs. Hope this helps!

6 0

3 years ago

Plz help.........................

Alex17521 [72]

The answer would be d

7 0

4 years ago

Randy can buy 6 gallons of gas for $18 or 7 gallons of gas for $21. how much do you think he would pay for 8 gallons of gas?

lesantik [10]

18/6 = 3 dollars per gallon

8 x 3 = 24

8 gallons would cost $24

answer is C

6 0

3 years ago

Read 2 more answers

Let $A = (4,-1)$, $B = (6,2)$, and $C = (-1,2)$. There exists a point $X$ and a constant $k$ such that for any point $P$,

goldfiish [28.3K]

Answer:

k=32

Step-by-step explanation:

Given the points:

$A = (4,-1)$, $B = (6,2)$, and $C = (-1,2)$.$

The first step is to find the Centroid of the triangle.

Centroid, X

$=\left(\dfrac{x_1+x_2+x_3}{3} ,\dfrac{y_1+y_2+y_3}{3} \right)\\=\left(\dfrac{4+6+(-1)}{3} ,\dfrac{-1+2+2}{3} \right)\\=\left(\dfrac{9}{3} ,\dfrac{3}{3} \right)=(3,1)$

Next, let P be a point (x,y)

Using the distance formula, $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$PA^2=(x-4)^2+(y-(-1))^2\\PB^2=(x-6)^2+(y-2)^2\\PC^2=(x-(-1))^2+(y-2)^2\\PX^2=(x-3)^2+(y-1)^2\\$

On Substitution into: $PA^2 + PB^2 + PC^2 = 3PX^2 + k$

$(x-4)^2+(y-(-1))^2+(x-6)^2+(y-2)^2+(x-(-1))^2+(y-2)^2=3[(x-3)^2+(y-1)^2]+k$

Let us simplify the LHS first

$\\LHS: x^2-8x+16+y^2+2y+1+x^2-12x+36+y^2\\-4y+4+x^2+2x+1+y^2-4y+4\\=3x^2-18x+3y^2-6y+62$

Also, the Right Hand Side

$RHS:3[(x-3)^2+(y-1)^2]+k\\=3[x^2-6x+9+y^2-2y+1]+k\\=3x^2-18x+27+3y^2-6y+3+k\\=3x^2+3y^2-18x-6y+30+k$

Therefore:

$3x^2-18x+3y^2-6y+62=3x^2+3y^2-18x-6y+30+k\\k=3x^2-18x+3y^2-6y+62-3x^2-3y^2+18x+6y-30\\k=3x^2-3x^2+3y^2-3y^2-18x+18x+62-30\\k=32$

7 0

3 years ago

Write an equation of a horizontal line that passes through the point (-2,2)

sergejj [24]

y = 2

A horizontal line, parallel to the x-axis has equation y = c

where c is the value of the y-coordinate the line passes through.

( - 2, 2) has y- coordinate of 2

equation of horizontal line is therefore y = 2

4 0

4 years ago

Read 2 more answers