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vazorg [7]
3 years ago
8

Plz help.........................

Mathematics
1 answer:
Alex17521 [72]3 years ago
7 0
The answer would be d 
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Word problem with multiplication and
natta225 [31]
6x26=156-7= 149

answer: 149
8 0
2 years ago
Aiden estimates the length is 7.2 but it’s 6.5 what’s the percent error
IrinaVladis [17]

Percent error is 10.7%

Step-by-step explanation:

We need to find the percent error:

We are given:

Estimate value = 7.2

Actual value = 6.5

Percent Error=?

The formula used is:

Percent\,\,Error=\frac{Estimate\,\,value-Actual\,\,value}{Actual\,\,value}\times100\\

Putting values:

Percent\,\,Error=\frac{7.2-6.5}{6.5}\times100\\Percent\,\,Error=\frac{0.7}{6.5}\times100\\Percent\,\,Error=0.107\times100\\Percent\,\,Error=10.7%\\

So, Percent error is 10.7%

Keywords: Percent Error

Learn more about Percent Error at:

  • brainly.com/question/4625002
  • brainly.com/question/82877
  • brainly.com/question/1834017

#learnwithBrainly

8 0
3 years ago
A room is 5m by 3m and has a height of 3.5m. Find the distance from a comer point on the floor to the opposite comer of the ceil
stiks02 [169]

Answer:

Approximately 6.8m

Step-by-step explanation:

We can picture this problem by drawing a rectangular prism with a width of 5m, a depth of 3m, and a height of 3.5m. To find the length from one corner of the floor to the opposite corner of the floor, we can use the pythagorean theorem and plug in the width and depth of the room for a and b:

5^{2}+3^{2}=c^{2}

And now we can solve for c...

34 = c^{2}

\sqrt{34}=\sqrt{c^{2}}

c = 5.831m

Now that we have the length from corner to corner across the floor, we can use the pythagorean theorem again, this time using the length from corner to corner across the floor we just derived and the height of the room:

5.831^{2} + 3.5^{2}=c^{2}

And now we can solve for c again...

46.25=c^{2}\\\sqrt{46.25}=\sqrt{c^2}

c = 6.8m

3 0
2 years ago
In each of the following ,make y the subject and hence find the value of y when a=2, b=3 ,and c=4.
zvonat [6]

Part i


\dfrac{2a-7}{6y} = \dfrac{3b-5}{2c}


y = \dfrac{ 2c(2a-7)}{6(3b-5)} = \dfrac{c(2a-7)}{9b-15}


Substituting,

y = \dfrac{4(2(2)-7)}{9(3)-15} = \dfrac{ -12}{12} = -1


Answer: -1


Part ii


I'm not sure that one's typed in correctly but I'll solve it as written.


3-34y + 2a = \dfrac{3b-5}{2c + 1}


34y  = 3+2a-\dfrac{3b-5}{2c + 1}


y = \frac 1 {34}\left(3+2a-\dfrac{3b-5}{2c + 1} \right)


We're not asked to simplify it so I wont. Substituting,


y = \frac 1 {34}\left(3+2(2)-\dfrac{3(3)-5}{2(4) + 1} \right) = \frac 1 {34}(7-4/9) = \dfrac{59}{306}


Answer: 59/306



3 0
3 years ago
Which statement is true about the two triangles?
mote1985 [20]
C is the correct answer

4 0
3 years ago
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