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Schach [20]
3 years ago
6

Please answer these I will give you all my points!

Mathematics
1 answer:
makvit [3.9K]3 years ago
5 0
  1. 300
  2. 59
  3. 4
  4. 78

ok so put it like that and it will be correct.............................................................................(long pause)........................................................................................................... (thinks) I think that the right answer.

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Here is the next questions brainliest to the first who answer it
qaws [65]

Answer:

Look at the attachment

7 0
3 years ago
What number is 120% of 12
Rasek [7]
120% of 12 is 14.4.I got this by doing this:

12/x=100/120
<span>(12/x)*x=(100/120)*x       - </span>we multiply both sides of the equation by x
<span>12=0.833333333333*x       - </span>we divide both sides of the equation by (0.833333333333) to get x
<span>12/0.833333333333=x </span>
<span>14.4=x </span>
<span>x=14.4</span>
5 0
3 years ago
Find sin(a)&amp;cos(B), tan(a)&amp;cot(B), and sec(a)&amp;csc(B).​
Reil [10]

Answer:

Part A) sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}

Part B) tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}

Part C) sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}

Step-by-step explanation:

Part A) Find sin(\alpha)\ and\ cos(\beta)

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

sin(\alpha)=cos(\beta)

Find the value of sin(\alpha) in the right triangle of the figure

sin(\alpha)=\frac{8}{14} ---> opposite side divided by the hypotenuse

simplify

sin(\alpha)=\frac{4}{7}

therefore

sin(\alpha)=\frac{4}{7}

cos(\beta)=\frac{4}{7}

Part B) Find tan(\alpha)\ and\ cot(\beta)

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

tan(\alpha)=cot(\beta)

<em>Find the value of the length side adjacent to the angle alpha</em>

Applying the Pythagorean Theorem

Let

x ----> length side adjacent to angle alpha

14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132

x=\sqrt{132}\ units

simplify

x=2\sqrt{33}\ units

Find the value of tan(\alpha) in the right triangle of the figure

tan(\alpha)=\frac{8}{2\sqrt{33}} ---> opposite side divided by the adjacent side angle alpha

simplify

tan(\alpha)=\frac{4}{\sqrt{33}}

therefore

tan(\alpha)=\frac{4}{\sqrt{33}}

tan(\beta)=\frac{4}{\sqrt{33}}

Part C) Find sec(\alpha)\ and\ csc(\beta)

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

sec(\alpha)=csc(\beta)

Find the value of sec(\alpha) in the right triangle of the figure

sec(\alpha)=\frac{1}{cos(\alpha)}

Find the value of cos(\alpha)

cos(\alpha)=\frac{2\sqrt{33}}{14} ---> adjacent side divided by the hypotenuse

simplify

cos(\alpha)=\frac{\sqrt{33}}{7}

therefore

sec(\alpha)=\frac{7}{\sqrt{33}}

csc(\beta)=\frac{7}{\sqrt{33}}

6 0
3 years ago
there are about 1.5 grams of fat in 1 tabespoon of humus.how many grams of fat are in 2 1/2 cups of hummus ?
Kipish [7]
We'll first we need to know the in 1 cup there is 16 tablespoon.
so we could multiply  we need 2 1/2 cup so that is 16 (1cup) + 16 (1cup) +8 (1/2 cup)= 40 tablespoons... and 1 tablespoon is 1.5 grams of fat then we multiply 40 times 1.5 .... This is equal to 60 grams fat
So there is 60 grams of fat in 2 1/5 cups of hummus.
6 0
3 years ago
Calculate the average time the car took to reach each checkpoint. Record the average time in Table D of your Student Guide. The
zhuklara [117]

The average time the car took to reach each checkpoint are:

  • 2.07
  • 3.16
  • 4.11
  • 4.92

<h3>Average time</h3>

Given:

Time  interval

1              2      3           4

2.02    3.17   4.12    4.93

2.05    3.07  3.98   4.81

2.15    3.25  4.23    5.01

Hence:

First quarter checkpoint

Average time= (2.02 + 2.05 + 2.15) / 3

Average time=6.22/3

Average time= 2.07s

Second quarter checkpoint

Average time= (3.17 +3.07 + 3.25) / 3

Average time=9.49/3

Average time = 3.16 s

Third quarter check point

Average time= (4.12 + 3.98 + 4.23) / 3

Average time=12.33/3

Average time= 4.11 s

Fourth quarter check point

Average time = (4.93 + 4.81 + 5.01) / 3

Average time=14.75/3

Average time= 4.917 s

Average time=4.92s (Approximately)

Therefore the average time the car took to reach each checkpoint are: 2.07, 3.16, 4.11, 4.92.

Learn more about average time here:brainly.com/question/19136062

#SPJ1

6 0
2 years ago
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