Area = length x width
area = 2 3/4 x 2/5
area = 1 1/10 feet :)
Step-by-step explanation:
I'll do the first problem as an example.
∠P and ∠H both have one mark. That means they're congruent.
∠T and ∠G both have two marks. So they're congruent.
∠W and ∠D both have three marks. So they're congruent.
So we can write a congruence statement:
ΔPTW ≅ ΔHGD
We can write more congruence statements by rearranging the letter, provided that corresponding pairs have the same position (P is in the same place as H, etc.). For example:
ΔWPT ≅ ΔDHG
ΔTWP ≅ ΔGDH
65Answer:
we can use sin to find the missing length
Step-by-step explanation:
The ratio states that sin of an angle=opposite/hypotenuse
sin(65)=x/6 since we know the angle and the hypotenuse we need to figure out the opposite side
sin(65)=0.906307...
0.906307=x/6
Multiply 6 on both sides to isolate x
The answer is 5.4378...
Rounded to the hundredth is 5.44
Assuming the 2,6,1 are length, width and height we can use the formula Volume= length • width • height. When you plug those in you will get 2•6•1= 12. The volume is 12 cubic millimeters. Or 12 cubed
Answer:
Step-by-step explanation:
You need to complete the square.
C(x) = 0.02(x^2 - 1000x ...) + 11000
C(x) = 0.02 (x^2 - 1000x + 500^2) + 11000 - 5000
C(x) = 0.02 (x^2 - 1000x + 500^2) + 6000
C(x) = 0.02(x - 500)^2 + 6000
Now if you look at the answer you will find that the square is completed. That means that number of tractors you could produce is 500 at a cost of 6000
There is a flow to this question that you may have trouble understanding.
First of all the 500^2. That comes from taking 1/2 of 1000 and squaring it. That's what you need to complete the square.
Bur that is not what you have adding into the equation. Remember that there is a 0.02 in front of the brackets.
500^2 = 250000
0.02 * 250000 = 5000
So that number must be subtracted to make the square = 0. When you remove the brackets, you should get 11000 all in all.
So what you have outside the brackets is 11000 - 5000 = 6000
The rest is just standard for completing the square.