Answer:
1. G° = -RT ln (G1P/P)
3.1 = 8.314 × 310 × ln (G1P/P)
3.1 / 2577.34 = ln (G1P/P)
0.0012 = ln (G1P/P)
0.0012 = (log G1P/P)/log 2.71828
0.4342 × 0.0012 = log G1P/P
0.00052 = log G1P/P
G1P/P = 10^0.00052 = 1.0012
P/G1P = 1/1.0012 = 0.9988
2. The cleavage of glycogen phosphorolytically is beneficial for the cell to conduct the process as the discharged glucose is phosphorylated. A general hydrolytic cleavage would give rise to only a glucose, which has to be phosphorylated again with the help of ATP.
Another merit of phosphorylated glucose is that it comprises the negative charge and cannot diffuse out of the muscle cell. Thus, the reaction will not be at equilibrium under the physiological conditions and always encourages the generation of the products. The formation of products will amend the change in free energy in such a manner that the reaction will always carry in the forward direction.
3. Greater the ratio of [Pi]/[glucose-1-phosphate], higher will be the relative rate of glycogen phosphorylase in comparison to the phosphoglucomutase as the transformation of Glu-1-P becomes slow because of lesser accessibility of substrate.
Answer:
C
Explanation:
This is a monohybrid cross between involving a gene coding for earlobe. The allele for free earlobe (F) is dominant over that of attached earlobe (f).
N.B: let F represent the gene involved.
A genotypic ratio is the ratio derived from the offsprings based on the actual genetic make-up and not based on their phenotypic appearance as in phenotypic ratio.
A homozygous individual is an individual having the same kind of alleles for a gene while a heterozygous individual is one that has two different alleles i.e. combination of the dominant and recessive allele.
The monohybrid cross is between an individual with attached earlobe (ff) i.e. homozygous recessive individual. (Note that, a recessive trait will only be expressed in a homozygous state) and a heterozygous free earlobeb individual (Ff). (See attached picture). Ff × ff
The resulting four offsprings will
be expected to have only two distinct genotypes i.e heterozygous (Ff) and homozygous recessive (ff) in an equal ratio i.e. 2:2 ~ 1:1
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