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olganol [36]
4 years ago
5

A trapezoid has bases that measure 10cm and 6cm. The height of the figure is 15cm. What is the area of the trapezoid?

Mathematics
1 answer:
kati45 [8]4 years ago
8 0
Hello!

To find the area of a trapezoid you use the equation

A = \frac{a+b}{2} h

A is area
h is height
a and b are the bases

Put in the values we know

A =  \frac{10+6}{2} *15

Add

A =  \frac{16}{2} *15

Divide

A = 8 * 15

Multiply

A = 120

The answer is 120cm squared

Hope this helps!
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goblinko [34]

Step-by-step explanation:

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  • In this case a=4,b=-6,c=1
  • Substitute into the quadratic formula:
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7 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all the tiles will be used.
victus00 [196]

Answer:

(5x)² ≥ 46

x² + 5x ≤ 46

5x² > 46

Step-by-step explanation:

Suppose number is x

<h3>1)</h3>

The square of the product of 5 and a number is not less than 46.

Step 1

Product of 5

5x

Step 2

Square of the product of 5

(5x)²

Step 3

A number is not less than 46

(5x)² ≥ 46

<h3>2)</h3>

The sum of square of a number and five times that number is no more than 46

Step 1

Square of a number

x²

Step 2

Five times that number

5x

Step 3

The sum

x² + 5x

Step 4

Is no more than 46

x² + 5x ≤ 46

<h3>3)</h3>

The product of 5 and the square of a number is greater than 46

Step 1

The square of a number

x²

Step 2

The product of 5

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Step 3

Is greater than 46

5x² > 46

6 0
3 years ago
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3 0
3 years ago
Natasha, Peter and Malachy share £56 in a ratio 1:1:2. How much money does each person get?
Rudiy27

Answer:

Natasha £14

Peter £14

Malachy £28

Step-by-step explanation:

Add 1+1+2=4

56/4=14

Multiple each ratio by 14 check by adding up and see if its the beginning total figure!

3 0
3 years ago
Simplify:<br><br> √27x^2y^2<br><br> A) 27xy<br> B) 3xy<br> C) 3xy√3<br> D) xy√27
iren2701 [21]

Answer:

\sqrt{27x^2y^2}=3xy\:\sqrt{3}

Hence, option C is correct.

Step-by-step explanation:

Given the expression

\sqrt{27x^2y^2}

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\sqrt{27x^2y^2}=\sqrt{27}\sqrt{x^2}\sqrt{y^2}

Apply radical rule: \sqrt{a^2}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

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Apply radical rule: \sqrt{a^2}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

                =\sqrt{27}xy

                =xy\sqrt{3^3}

                 =xy\sqrt{3^2\cdot \:\:3}

Apply radical rule: \sqrt{a^2}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

                  =3xy\:\sqrt{3}

Therefore,

\sqrt{27x^2y^2}=3xy\:\sqrt{3}

Hence, option C is correct.

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