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Reptile [31]
3 years ago
8

Trigonometry please help! work need to be shown

Mathematics
1 answer:
Tpy6a [65]3 years ago
3 0

Given:

The figure of a right angle triangle.

To find:

The value of x to the nearest hundredth.

Solution:

In a right angle triangle,

\cos \theta=\dfrac{Base}{Hypotenuse}

Using the above trigonometric ratio for the given triangle, we get

\cos 46^\circ=\dfrac{x}{8}

0.6947=\dfrac{x}{8}

0.6947\times 8=x

5.5576=x

Approximate the value to the nearest hundredth.

x\approx 5.56

Therefore, the value of x is 5.56 units.

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3 years ago
To find the angle of rotation θ between the previous x and y axes and the new x′ and y′ axes, we use the formula: cotangent of 2
Tamiku [17]

The equation is the given one:

\cot 2\theta=\frac{A-C}{B}

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7 0
1 year ago
(-1,-6) and (-3,-8) y=Mx+b
denpristay [2]

Answer:

m = 1, b = -5         y = x -5

Step-by-step explanation:

first find the slope or m

slope is change in y over change in x

-8 - (-6) = -2

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use one of the points and solve for b

7 0
3 years ago
HELPPPP PLEASE<br>60 POINTS​
soldi70 [24.7K]

Answer:

1056

Step-by-step explanation:

Find the area of each square and add them to find the area of the rectangle

The area of a square = side * side

The areas are:

1*1= 1

4*4 = 16

7*7 = 49

8*8 = 64

9*9 = 81

10*10 = 100

14*14 = 196

15*15 = 225

18*18 = 324

The sum of the areas =

324+225+196+100+81+64+49+16+1

= 1056 units ^2

3 0
3 years ago
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In how many distinct ways can the letters of the word mathematics be arranged? (first, does the order matter?)
TEA [102]
Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).

Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
4 0
3 years ago
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