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kow [346]
3 years ago
14

FIND THE INDICATED PROBABILITY

Mathematics
2 answers:
Rudiy273 years ago
5 0
Total number of people = 66 + 98 =  164

P(a woman selected) = 66 / 164 = 33/82
kvv77 [185]3 years ago
5 0

Answer:

D) 33/82

Step-by-step explanation:

Given:

The number of women in the class = 66

The number of men in the class = 98

Now we have to find the total number of students.

The total number of students in the class = 66 + 98 = 164

We know that, the probability of an event = The number of favorable outcomes / The total number of possible outcomes.

Here we are asked to find the probability that the student is a women.

The number of favorable outcomes = 66 and the total number of possible outcomes = 164.

So, the probability that the student is a woman = \frac{66}{164}

We can simplify this fraction. Here GCF of 66 and 164 is 2. So we need to divide both the numerator and the denominator by 2, we get

= \frac{33}{82}

The answer is D) 33/82

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Solve the equation.<br> 4+ 14 = – 2(7x-9)
Tamiku [17]

Answer:

-63

Step-by-step explanation:

4 0
3 years ago
Formula for the volume of a square pyramid, v=1/3lwh for w
tatuchka [14]

\dfrac{1}{3}lwh=V\qquad|\text{multiply both sides by 3}\\\\lwh=3V\qquad|\text{divide both sides by}\ lh\neq0\\\\\boxed{w=\dfrac{3V}{lh}}

3 0
3 years ago
a class has ten girls and three boys. if the teacher randomly picks ten students,what is the probability that he will pick all g
grin007 [14]

Answer:

10/13

Step-by-step explanation:

You will first add all the students the mentioned which gives you 13 then since they ask what is the probability it the teacher would pick girls. You know there's 10 girls and 3 boys so it would be 10/13.                                  

7 0
2 years ago
According to a recent​ survey, the population distribution of number of years of education for​ self-employed individuals in a c
creativ13 [48]

Answer:

a) X: number of years of education

b) Sample mean = 13.5, Sample standard deviation = 0.4

c) Sample mean = 13.5, Sample standard deviation = 0.2

d) Decrease the sample standard deviation

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 13.5 years

Standard deviation,σ = 2.8 years

a) random variable X

X: number of years of education

Central limit theorem:

If large random samples are drawn from population with mean \mu and standard deviation \sigma, then the distribution of sample mean will be normally distributed with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

b) mean and the standard for a random sample of size 49

\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{49}} = 0.4

c) mean and the standard for a random sample of size 196

\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{196}} = 0.2

d) Effect of increasing n

As the sample size increases, the standard error that is the sample standard deviation decreases. Thus, quadrupling sample size will half the standard deviation.

7 0
3 years ago
Rectangle MNPQ is similar to rectangle RSTU. Given the information marked on the diagram, what is the perimeter of RSTU?
xenn [34]
The perimeter of RSTU can be calculated alone without the help of MNPQ. It would be just 2(4) + 2(3) = 14 units. However, it would be much sensible if you want to find the parameter of the bigger rectangle. Since they are similar, you could use ratio and proportion.

(length/width)∨MNPQ = (length/width)∨RSTU
(x/9) = (3/4)
x = 6.75 units

Thus the perimeter of MNPQ is 2(6.75) + 2(9) = 31.5 units
5 0
2 years ago
Read 2 more answers
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