For an individual die roll, the probability of rolling 6 is \dfrac{1}{6}
6
1
.
Effectively, this problem is asking for P(\text{1st roll is 6}\cap\text{2nd roll is 6})P(1st roll is 6∩2nd roll is 6).
Using the rule of product, this is:
\dfrac{1}{6}\times\dfrac{1}{6}=\dfrac{1}{36}
6
1
×
6
1
=
36
1
.
r= 9 because 45/5 is 9 and it works the same way for the rest of the problems.
Answer:
9 Cards
Step-by-step explanation:
9 Cards a day equals 27 cards in 3 days
Scores could be : 0,1,...10 (11 scores)
a. P=1/11
b. could take 8,9 or 10 points ( 3 scores)
P=3/11
c. could 5,4,3,2,1,or 0 points (6 scores)
P=6/11
d. could take 6,7,8,9 ( 4 scores)
P=4/11
Answer:
Step-by-step explanation:
<u>Given</u>
- The dimensions of the lot are (6+x) feet and (6−x) feet
- The dimensions of the house to be (2+x) feet and (2−x) feet
Area of the yard = Area of the lot - Area of the house
<u>Area of the yard:</u>
- (6 + x)(6 - x) - (2 + x)(2 - x) =
- 36 - x² - 4 + x² =
- 32 square feet
<u>If the house is extended, then the area of the yard will change as:</u>
- (6 + x)(6 - x) - (4 + x)(4 - x) =
- 36 - x² - 16 + x² =
- 20 square feet