1. Factoring a quadratic expression ax2 + bx + c, where a ≠ 1, is different from factoring x2 + bx + c because for the former type of expression you have to factor out the value of "a". Then, proceed to the factoring steps as usual.
2. To confirm the equations to be equal with the parent function we do as follows:
<span> (2x – 4)(x + 5) = 2x^2 + 10x - 4x - 20 = 2x^2 + 6x -20
</span><span>(x – 2)(2x + 10) = 2x^2 +10x - 4x -20 = 2x^2 +6x - 20
3. The roots of the quadratic expression represents the values of x that would satisfy the expression. The x-intercepts are the values of x when y is equal to zero, it is where the plot touches intersects the x-axis.</span>
It's two. 50% chance of heads, 50% chance of tails.
Answer: 3log5(2) - 1 or ~0,29203
Step-by-step explanation:
2log5(4) - log5(10)
log5(4^2) - log5(10)
log5(4^2/10)
log5(16/10)
log5(8/5)
Log5(8) - log5(5)
log5(2^3) - 1
3log5(2) - 1
Answer:
1. -7.5
2. $1
3. 40
Step-by-step explanation:
For number 1, it can be solved by using the PEMDAS method, or see explanation below:
6x - 4x - 36 = 6 - 2x
2x - 36= -2x + 6
4x + 36 = 6
4x = -30
x = -15/2 or -7.5
For number 2, substitute 3 into both equations:
f(x) =1.50(3) + 2.00
and
f(x) = 2.00(3) + 1.50
This would get $6.50 and $7.50, which, if subtracted, gets $1.
For number 3, do something similar to the previous problem. Substitute 3 for x. It would be 5(2^3), or 40.
Hope this helps!
First introduce the following notations:
