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mariarad [96]
3 years ago
12

Algebra!!! 3 Questions Only take if you know ALL Answers PLZZZ QUICK

Mathematics
1 answer:
vitfil [10]3 years ago
7 0

Answer:

1. -7.5

2. $1

3. 40

Step-by-step explanation:

For number 1, it can be solved by using the PEMDAS method, or see explanation below:

6x - 4x - 36 = 6 - 2x

2x - 36= -2x + 6

4x + 36 = 6

4x = -30

x = -15/2 or -7.5

For number 2, substitute 3 into both equations:

f(x) =1.50(3) + 2.00

and

f(x) = 2.00(3) + 1.50

This would get $6.50 and $7.50, which, if subtracted, gets $1.

For number 3, do something similar to the previous problem. Substitute 3 for x. It would be 5(2^3), or 40.

Hope this helps!

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HELP!!!
ella [17]

Answer:

120

Step-by-step explanation:

We are given that the function for the number of students enrolled in a new course is f(x) = 4^{x}-1.

It is asked to find the average increase in the number of students enrolled per hour between 2 to 4 hours.

We know that the average rate of change is given by,

A = \frac{f(x)-f(a)}{x-a},

where f(x)-f(a) is the change in the function as the input value (x-a) changes.

Now, the number of students enrolled at 4 = f(4) = f(x) = 4^{4}-1 = 255 and the number of students enrolled at 2 = f(2) = f(x) = 4^{2}-1 = 15

So, the average increase A=\frac{f(4)-f(2)}{4-2} = A=\frac{255-15}{4-2} = A=\frac{240}{2} = 120.

Hence, the average increase in the number of students enrolled is 120.

3 0
4 years ago
The interest that cindy earns on her investment is given by the equation /=42t where t is the time in years that her money is in
Len [333]

Answer:


Equation is 42t

So,

t=12

According to equation

Put value of t

=42(12)

=504

So 2nd option is correct.

5 0
3 years ago
A baby who was 18 inches at birth is now 24 inches by what percentage did the babys height increase
Kazeer [188]

Answer:

≈33.3%

Step-by-step explanation:

First we find the difference of the heights to see what the growth was

24-18 = 6

Then we find what percent 6 is of 18 to see what percentage growth occured

6/18 ≈33.3%

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=6%20%5Cdiv%20131.4" id="TexFormula1" title="6 \div 131.4" alt="6 \div 131.4" align="absmiddle"
Svetradugi [14.3K]

Answer: 21.9

131.4 divided by 6

4 0
3 years ago
Line g passes through points (5, 9) and (3, 2). Line h passes through points (9, 10) and (2, 12). Are line g and line h parallel
icang [17]

For this case we find the slopes of each of the lines:

The g line passes through the following points:

(x_ {1}, y_ {1}) :( 3,2)\\(x_ {2}, y_ {2}) :( 5,9)

So, the slope is:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {9-2} {5-3} = \frac {7} {2}

Line h passes through the following points:

(x_ {1}, y_ {1}) :( 9,10)\\(x_ {2}, y_ {2}) :( 2,12)

So, the slope is:

m = \frac {y_ {2} -y_ {1}}{x_ {2} -x_ {1}} = \frac {12-10} {2-9} = \frac {2} {- 7} = - \frac {2} {7}

By definition, if two lines are parallel then their slopes are equal. If the lines are perpendicular then the product of their slopes is -1.

It is observed that lines g and h are not parallel. We verify if they are perpendicular:

\frac {7} {2} * - \frac {2} {7} = \frac {-14} {14} = - 1

Thus, the lines are perpendicular.

Answer:

The lines are perpendicular.

8 0
3 years ago
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