Are you trying to find x? send the whole question xoxo
x = 3 + y Eqn(1)
y = -2x + 9 Eqn(2)
Let us solve the system of equations with the substitution method
x - 3 = y (Subtracting 3 from both sides of the Eqn(1))
Replacing y = x - 3 in Eqn (2), we have:
x - 3 = -2x + 9
x = -2x + 9 + 3 (Adding 3 to both sides of the equation)
x + 2x = 9 + 3 (Adding 2x to both sides of the equation)
3x = 12 ( Adding like terms)
x = 12/3 (Dividing by 3 on both sides of the equation)
x = 4
Replacing x=4 in Eqn(1), we have:
4 = 3 + y
4 - 3 = y (Subtracting 3 from both sides of the equation)
y=1
The answers are:
x= 4 and y=1
Answer:
The square root of 121.
Step-by-step explanation:
The square root of 121 is 11. 11x11=121 which makes the square root of 121, 11. The cube root of 125 is 5. Cube roots are numbers that are multiplied by each other to make a number, 125 is 5x5x5 so the cube root is 5. 11 is a greater number than 5 which makes the square root of 121 greater.
First, you make 9 into a fraction which would become 36/4
then, subtract 9/4 from both sides so that would give you 3/4x = 27/4
then divide each side by 3/4 (same thing as multiply by its reciprocal) and that would give you x=9
8.9 really hope this helps little bro