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3 years ago

14

There is a 100 question exam, each right question answered is +1 point, each wrong question answered is -05 point. A student got

8.05 in the exam, how many wrong and right questions did the student do?

2 answers:

zhenek [66]3 years ago

8 0

Answer:

bbbbbbbbbbbbbbbbbbbbb

Step-by-step explanation:

earnstyle [38]3 years ago

6 0

Two feet is sixteen inches so ghetto is twenty for inches so the answer is teo

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Answer my questions and i will mark you as brainliest i promise trust me

Kazeer [188]

Answer:

1.042g/cm^3

Step-by-step explanation:

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4 years ago

14 through 19 whole problem solving and answers

Sergio039 [100]

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3 years ago

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In △ABC, D is a point on side AC¯¯¯¯¯¯¯¯ such that BD=DC and ∠BCD measures 70∘. What is the degree measure of ∠ADB?

777dan777 [17]

If angle BCD measures 70° then so does angle DBC (because you have formed an isoceles triangle inside the larger ΔABC and the two legs are equal so the two angles have to be equal. So we have a two 70° angles which leaves 40° for the 3rd angle, which is ∠BDC.

Since ∠BDC and ∠ADB are supplementary (180°) - that leaves 140° for ∠ADB and is our answer

5 0

3 years ago

As a bicycle salesperson, Norman earns a fixed salary of $20 per week plus $6 per bicycle for the first 6 bicycles he sells, $12

wlad13 [49]

Answer:

A. I only

I. y>2x

Step-by-step explanation:

I. y>2x

He sold x bicycles last week and y bicycles this week, this week, he earned more than twice as much as he did last week. Therefore more than twice means greater than 2 x or

y>2x

II. y>x This is not true because y could be greater than x and less than twice of x (2x)

III. y>3 This is also not true because the least he would be earning would be $ 20 and he could get earn greater than 3 and less than $ 20 which would again be contradictory to the given statement

4 0

3 years ago

Match each set of vertices with the type of triangle they form.

Andrew [12]

Answer: The calculations are done below.

Step-by-step explanation:

(i) Let the vertices be A(2,0), B(3,2) and C(5,1). Then,

$AB=\sqrt{(2-3)^2+(0-2)^2}=\sqrt{5},\\\\BC=\sqrt{(3-5)^2+(2-1)^2}=\sqrt{5},\\\\CA=\sqrt{(5-2)^2+(1-0)^2}=\sqrt{10}.$

Since, AB = BC and AB² + BC² = CA², so triangle ABC here will be an isosceles right-angled triangle.

(ii) Let the vertices be A(4,2), B(6,2) and C(5,3.73). Then,

$AB=\sqrt{(4-6)^2+(2-2)^2}=\sqrt{4}=2,\\\\BC=\sqrt{(6-5)^2+(2-3.73)^2}=\sqrt{14.3729},\\\\CA=\sqrt{(5-4)^2+(3.73-2)^2}=\sqrt{14.3729}.$

Since, BC = CA, so the triangle ABC will be an isosceles triangle.

(iii) Let the vertices be A(-5,2), B(-4,4) and C(-2,2). Then,

$AB=\sqrt{(-5+4)^2+(2-4)^2}=\sqrt{5},\\\\BC=\sqrt{(-4+2)^2+(4-2)^2}=\sqrt{8},\\\\CA=\sqrt{(-2+5)^2+(2-2)^2}=\sqrt{9}.$

Since, AB ≠ BC ≠ CA, so this will be an acute scalene triangle, because all the angles are acute.

(iv) Let the vertices be A(-3,1), B(-3,4) and C(-1,1). Then,

$AB=\sqrt{(-3+3)^2+(1-4)^2}=\sqrt{9}=3,\\\\BC=\sqrt{(-3+1)^2+(4-1)^2}=\sqrt{13},\\\\CA=\sqrt{(-1+3)^2+(1-1)^2}=\sqrt 4.$

Since AB² + CA² = BC², so this will be a right angled triangle.

(v) Let the vertices be A(-4,2), B(-2,4) and C(-1,4). Then,

$AB=\sqrt{(-4+2)^2+(2-4)^2}=\sqrt{8},\\\\BC=\sqrt{(-2+1)^2+(4-4)^2}=\sqrt{1}=1,\\\\CA=\sqrt{(-1+4)^2+(4-2)^2}=\sqrt{13}.$

Since AB ≠ BC ≠ CA, and so this will be an obtuse scalene triangle, because one angle that is opposite to CA will be obtuse.

Thus, the match is done.

4 0

3 years ago

Read 2 more answers