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dlinn [17]
3 years ago
12

Question one I need the answer to please

SAT
1 answer:
lions [1.4K]3 years ago
8 0

A is your answer

If they don’t know what happened to them and they look hurt because of the lightning people think that someone hurt them because it’s unlikely when someone gets struck by lighting because it’s unlikely.

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Prices to a concert cost N$200 for an adult and N$150 for a child, the concert venue can accommodate at most 240 people. The org
faust18 [17]

Answer:

i. 240 tickets

ii. 80 adults and 160 children

iii. N$ 40,000.00

iv. Profit= N$ 36,800.00

Explanation:

Ok so in order to solve this problem we need to start by building our system of equations from the restrictions the problem gives us:

let's say that

x=# of adult tickets

y= # of children tickets

so

"... the concert venue can accommodate at most 240 people."

this translates to the following inequality:

x+y\leq240

"The organizeres are giving a N$20 discount to every adult and N$10 discount for every child but do not want the total descounted amount to exceed N$3200."

Translates to

20x+10y\leq3200

and we know we cannot sell a negative number of adult and children tickets so the last restrictions are:

x\geq0

y\geq0

so we can now graph our system of inequalities (see graph attached)

the procedure to graph a linear equation is as follows:

1. Pick an x-value

2. Find the corresponding y-value with the provided equation we need to graph.

3. Write the coordinates as an ordered pair (x,y)

4. Repeat the process with a second x-value.

5. Graph the two points you found on the previous steps.

6. Connect the points with a straight line.

So the feasible region is the one that all restrictions will have in common and the maximum and minimum points for our objective function will be the marked points, which are the vertices of the feasible region. So we test them to see which will maximize our objective function.

Objective function:

s=200x+150y

(0,0)

s=200(0)+150(0)=0

(0,240)

s=200(0)+150(240)=N$36,000

(80,160)

s=200(80)+150(160)=N$40,000

(160,0)

s=200(160)+150(0)=N$32,000

So when comparing the results we can see that the objective function will be maximized at the point (80,160) so:

i) How many tickets altogether should the organisers sell in order to maximize their sales amount?

total # of tickets = x+y = 80+160=240 tickets

ii) How many tickets of each type (adult and child) should they sell to get a maximum sales amount?

x                                   y

80 adult tickets and 160 child tickets.

iii) What is the maximum sales amount the organizers can make?

s=200(80)+150(160)=N$40,000

iv) If the profit is calculated as follows: profit = total sales - total discount amount. How much profit will the organisers make from the maximum sales?

Profit= total sales - total discount

total sales=200(80)+150(160)=N$40,000

total discount = 20(80)+10(160)=N$3,200

Profit=N$40,000-N$3,200=N$36,800.00

8 0
3 years ago
After studying until four in the morning, I was a bit sleepy
kow [346]

Answer:

understandment or anything

6 0
2 years ago
Read 2 more answers
Where would an air mass thunderstorm most likly occur
Arisa [49]
In a cool unstable environment
3 0
3 years ago
Which notes do we say "ta, ti-ti" for?
vovangra [49]

Answer:

In the general rhythm counting system, you say “ta” for quarter notes and “ti ti” for eighth notes.

Explanation:

4 0
3 years ago
The function f is continuous on the interval (0,16), and f is twice differentiable except at x=5 where the derivatives are undef
Oliga [24]

Using it's definition, it is found that the function f(x) has a point of inflection at:

A. x = 8 only.

<h3>What are the points of inflection of a function?</h3>
  • The critical points of a function are the <u>values of x</u> for which:

f^{\prime\prime}(x) = 0

  • Additionally, there has to be a change in the sign of f^{\prime\prime}(x)

Researching the problem on the internet, it is found that:

  • For 0 < x < 5, f^{\prime\prime}(x) > 0.
  • For x = 5, f^{\prime\prime}(x) is undefined.
  • For 5 < x < 8, f^{\prime\prime}(x) < 0.
  • For x = 8, f^{\prime\prime}(x) = 0.
  • For 8 < x < 12, f^{\prime\prime}(x) > 0.
  • For x = 12, f^{\prime\prime}(x) = 0.
  • For 12 < x < 16, f^{\prime\prime}(x) > 0.

The two conditions, f^{\prime\prime}(x) = 0 and a change in the signal of f^{\prime\prime}(x) are only respected at x = 8, which is the lone inflection point.

You can learn more about points of inflection at brainly.com/question/10352137

7 0
2 years ago
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