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3 years ago

11 ounces to 5 ounces

Mathematics

2 answers:

Maurinko [17]3 years ago

6 0

Answer:

(11/5) (a ratio)

Step-by-step explanation:

11 ounces to 5 ounces could be rewritten as

11 oz.

---------- = (11/5) (a ratio)

5 oz

harkovskaia [24]3 years ago

4 0

Answer: what is the question to this?

Step-by-step explanation: thanks let me know okay

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Erica is participating in a road race. The first part of the race is on a 5.2-mile-long straight road-oriented at an angle of 25

kap26 [50]

Answer:

6.31 mi

Step-by-step explanation:

The diagram below explains the solution better.

From the diagram,

C = starting point of the race.

A = end of the first part of the race.

B = end of the race.

Using Cosine rule, we can find the straight-line distance between the starting point and the end of the race.

Cosine rule states that:

$a^2 = b^2 + c^2 - 2bc[cos(A)]$

where A = angle A = <A

Given that

b = 5.2 miles

c = 2.0 miles

<A = 115° (from the diagram)

Hence,

$a^2 = 5.2^2 + 2.0^2 - 2*5.2*2.0[cos(115)]\\\\a^2 = 27.04 + 4 - 20.8[cos(115)]\\\\a^2 = 31.04 + 8.79\\\\a^2 = 39.83\\\\a = \sqrt{39.83}\\ \\a = 6.31 mi$

The straight-line distance between the starting point and the end of the race is 6.31 mi

4 0

2 years ago

NEED ANSWER ASAP!

sveta [45]

Answer:

the answer is c

4.5feets

30 feets

7 0

2 years ago

Although five of John's answers were incorrect, 90% of his answers were correct. How many questions did John answer in all?

fiasKO [112]

Answer:

John answered 50 questions.

Step-by-step explanation:

Although five of John's answers were incorrect, 90% of his answers were correct.

This means that 5 is 100 - 90% = 10% of the total number of questions, n. So

$0.1n = 5$

$n = \frac{5}{0.1}$

$n = 50$

John answered 50 questions.

7 0

2 years ago

From a balloon 915 feet high, the angle of depression to the ranger headquarters is 85°14'. How far is the headquarters from a p

zalisa [80]

<span>tan(85°14') = 915/d
hope this helps

</span>

3 0

2 years ago

Find a point on the ellipsoid x2+y2+4z2=36x2+y2+4z2=36 where the tangent plane is perpendicular to the line with parametric equa

Anvisha [2.4K]

Answer:

A point on the ellipsoid is (-4,2,2) or (4,-2,-2)

Step-by-step explanation:

Given equation of ellipsoid f(x,y,z) : $x^2+y^2+4z^2=36$

Parametric equations:

x=-4t-1

y=2t+1

z=8t+3

Finding the gradient of function

$\nabla f(x,y,z)=\\\nabla f(x,y,z)=$

So, The directions vectors=(-4,2,8)

Now the line is perpendicular to plane when direction vector is parallel to the normal vector of line

$\nablaf(x,y,z)=(2x,2y,8z)=\lambda(-4,2,8)$

So, $2x=-4\lambda$

$\Rightarrow x=-2\lambda$

$2y=2\lambda\\\Rightarrow y=\lambda\\8z=8\lambda\\\Rightarrow z=\lambda$

Substitute the value of x , y and z in the ellipsoid equation

$(2\lambda)^2+(\lambda)^2+4(\lambda)^2=36\\9(\lambda)^2=36\\\lambda^2=4\\\lambda=\pm 2$

With $\lambda = 2$

x=-2(2)=-4

y=2

z=2

With $\lambda =- 2$

x=-2(-2)=4

y=-2

z=-2

Hence a point on the ellipsoid is (-4,2,2) or (4,-2,-2)

7 0

3 years ago