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bearhunter [10]
3 years ago
15

Can somebody help me please.

Mathematics
1 answer:
Fiesta28 [93]3 years ago
7 0
I’m pretty sure it is 57?
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An SRS of size 20 is drawn from a population that has a normal distribution. The sample has a mean of 122.5 and a standard devia
Tems11 [23]

Answer:

The value is  \sigma_{\= x} = 1.789

Step-by-step explanation:

From the question we are told that

   The sample size is  n =  20  

    The sample mean is \= x = 122.5

    The standard deviation is  s =  8

Generally the standard error of the mean is mathematically represented as

       \sigma_{\= x} =  \frac{s}{\sqrt{n} }

=>    \sigma_{\= x} =  \frac{8}{\sqrt{20 } }

=>    \sigma_{\= x} = 1.789

8 0
3 years ago
Complete the square to write the equation, 4x2 + 24x – y + 43 = 0, in standard form.
Tamiku [17]

Answer:

y=4

x=3

7

Step-by-step explanation:

Edg2021

5 0
2 years ago
Read 2 more answers
Samuel walks forward 19 steps. He represents this movement with a positive 19. How would he represent the opposite of this numbe
spayn [35]

Answer: -38

Step-by-step explanation:

First he would have to walk back 19 steps to get back to his orginal position, then he would have to further go back another 19 steps.

7 0
3 years ago
If someone could please help me then that would be great.
postnew [5]

Answer: Infinite Solutions

Step-by-step explanation: Make the top x and y values times -2 to cancel all the variables and numbers out to get 0 = 0 so it would be Infinite Solutions.

And if you multiply by 2 you get the exact same equation.

If I am wrong let me know!

Hope this helps!  

6 0
3 years ago
Find the sum of the first 17 terms of the arithmetic sequence 10, 14, 18, 22, 26...
kari74 [83]
10, 14, 18 ....

notice, we get the next term by simply adding 4 to the current term, thus "4" is the "common difference, and we know that 10 is the first term.

\bf n^{th}\textit{ term of an arithmetic sequence}
\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=10\\
d=4\\
n=17
\end{cases}
\\\\\\
a_{17}=10+(17-1)(4)\implies a_{17}=10+(16)(4)
\\\\\\
a_{17}=10+64\implies a_{17}=74\\\\
-------------------------------

\bf \textit{ sum of a finite arithmetic sequence}
\\\\
S_n=\cfrac{n(a_1+a_n)}{2}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
----------\\
a_1=10\\
a_{17}=74\\
n=17
\end{cases}
\\\\\\
S_{17}=\cfrac{17(10+74)}{2}\implies S_{17}=\cfrac{17(84)}{2}\implies S_{17}=714
6 0
2 years ago
Read 2 more answers
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