Can somebody help me please.

The 1,840 rock concert tickets sold were twice the amount of jazz concert tickets sold. <br><br>

Vanyuwa [196]

Ur gay. Jeydydhushwusfb

5 0

3 years ago

Azul spun a tri-color spinner twice. What is the probability that the spinner landed on the colors blue and green in any order?

guapka [62]

Answer:

The Probability that the spinner landed on the colors blue and green in any order = 2/9

Step-by-step explanation:

Given - Azul spun a tri-color spinner twice.

To find - What is the probability that the spinner landed on the colors blue and green in any order?

Solution -

Given that,

A tri-color spinner spun twice

So,

The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}

⇒n(S) = 9

Now,

Let A be an event that the spinner landed on the colors blue and green

So,

A = {BG, GB}

⇒n(A) = 2

Now,

Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)

= 2 ÷ 9

∴ we get

The Probability that the spinner landed on the colors blue and green in any order = 2/9

8 0

3 years ago

Y = x - 2<br> y = 3x + 4

faust18 [17]

Answer:

How does it need solved? By graphing? Substitution?

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

I need help with this problem and I need it today

ANTONII [103]

Answer:

2d shape and the area is i think 3

Step-by-step explanation:

6 0

3 years ago

A recent study found that the average length of caterpillars was 2.8 centimeters with a

pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

$\mu = 2.8, \sigma = 0.7$ .

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4 - 2.8}{0.7}$

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

4 0

2 years ago